Answer:
1.67 m/s
Explanation:
Since this is an inelastic collision (the block and the arrow stick together after the collision), we can solve the problem by using the law of conservation of momentum:
where
is the mass of the arrow
is the initial speed of the arrow
is the mass of the block
is the initial speed of the block
is the final speed of the arrow+block
Substituting and re-arranging the equation, we find:
Answer:
Equivalent
A conversion factor is a ratio of <u>e</u><u>quivalent</u> measures
Answer:
A and D
Explanation:
Acceleration is the active change in speed, increasing or decreasing.
The speed after 21 s is 18.9 m/s and the total time required for the train to reach a speed of 34 m/s is 14.4 s
<h3>
What is Speed ?</h3>
Speed is a distance travelled by a body per time taken. It is a scalar quantity and it is measured in m/s
Given that at Initially stationary, a train has a constant acceleration of 0.9 m/s2.
(a) What is its speed after 21 s?
- Acceleration a = 0.9 m/s²
Using v = u + at
Substitute all the parameters into the equation
v = 0 + 0.9 x 21
v = 18.9 m/s
(b) What is the total time required for the train to reach a speed of 34 m/s?
Let first calculate for total distance by using
v² = u² + 2as
34² = 18.9² + 2 × 0.9 × S
1156 = 357.21 + 1.8S
1.8S = 1156 - 357.21
1.8S = 798.79
S = 798.79 / 1.8
S = 443.8 m/s
v = u + at
34 = 21 + 0.9t
0.9t = 34 - 21
0.9t = 13
t = 13/0.9
t = 14.44s
Therefore, its speed after 21 s is 18.9 m/s and the total time required for the train to reach a speed of 34 m/s is 14.4 s
Learn more about Speed here: brainly.com/question/24739297
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Hi there!
Use the following equation: (Newton's Second Law)
∑F = ma, where:
∑F = net force (J)
m = mass (kg)
a = acceleration (m/s²)
Plug in the given values:
∑F = 1500 · 40 = <em>60,000 J</em>