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1 year ago

Find the value of the trig functions indicated .

Mathematics

1 answer:

lara31 [8.8K]1 year ago

4 0

Answer:

The choice; B) 5/3

Step-by-step explanation:

${a}^{2} + {b}^{2} = {c}^{2} \\ {15}^{2} + {20}^{2} = {c}^{2} \\ 225 + 400 = {c}^{2} \\ {c}^{2} = 625 \\ c = 25$

$\sec(θ) = \frac{1}{ \cos(θ) } \\ \\ \sec(θ) = \frac{1}{ \frac{adjacent}{hypotenuse} } = \frac{hypotenuse}{adjacent} \\ \\ \sec(θ) = \frac{25}{15} = \frac{25 \div 5}{15\div 5} = \frac{5}{3}$

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3 years ago

Here are summary statistics for randomly selected weights of newborn girls: nequals=174174, x overbarxequals=30.930.9 hg, seq

MaRussiya [10]

Answer:

The 95% confidence interval would be given by (29.780;32.020)

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=30.9$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s=7.5 represent the sample standard deviation

n=174 represent the sample size

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=174-1=173$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a tabel to find the critical value. The excel command would be: "=-T.INV(0.025,173)".And we see that $t_{\alpha/2}=1.97$ , this value is similar to the obtained with the normal standard distribution since the sample size is large to approximate the t distribution with the normal distribution.

Now we have everything in order to replace into formula (1):

$30.9-1.97\frac{7.5}{\sqrt{174}}=29.780$

$30.9+1.97\frac{7.5}{\sqrt{174}}=32.020$

So on this case the 95% confidence interval would be given by (29.780;32.020)

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3 years ago

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Answer:

Step-by-step explanation:

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B is a geometric sequence with first term 1 and common ratio 1/2.

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3 years ago

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Answer:

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Step-by-step explanation:

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