Question

Find the value of the trig functions indicated .

Answer 1

Answer:

The choice; B) 5/3

Step-by-step explanation:

${a}^{2} + {b}^{2} = {c}^{2} \\ {15}^{2} + {20}^{2} = {c}^{2} \\ 225 + 400 = {c}^{2} \\ {c}^{2} = 625 \\ c = 25$

$\sec(θ) = \frac{1}{ \cos(θ) } \\ \\ \sec(θ) = \frac{1}{ \frac{adjacent}{hypotenuse} } = \frac{hypotenuse}{adjacent} \\ \\ \sec(θ) = \frac{25}{15} = \frac{25 \div 5}{15\div 5} = \frac{5}{3}$