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qaws [65]
2 years ago
15

HELP ASAP ITS TIMED

Mathematics
2 answers:
valina [46]2 years ago
4 0

Answer:

x+10=x^2+2x+1

Step-by-step explanation:

Given equation:

\sqrt{x+10}-1=x

Add 1 to both sides:

\implies \sqrt{x+10}-1+1=x+1

\implies \sqrt{x+10}=x+1

Square both sides:

\implies (\sqrt{x+10})^2=(x+1)^2

\implies \sqrt{x+10}=(x+1)(x+1)

Simplify:

\implies \sqrt{x+10}=x(x+1)+1(x+1)

\implies \sqrt{x+10}=x^2+x+x+1

\implies x+10=x^2+2x+1

Natasha_Volkova [10]2 years ago
3 0

Answer:

  x + 10 = x² + 1

(third option listed)

Step-by-step explanation:

assuming that you meant: \sqrt{x+10-1}=x  , because otherwise there would be no equivalent relationships,

(goal: isolate x on one side of the equation whilst having x on the other side of the equation also, like the equation in the question)*

   x + 10 = x² + 1

        -1            -1

   x + 10 - 1 = x²

  \sqrt{x+10-1} =\sqrt{x^2}                  [find √ of both sides to isolate x]

\sqrt{x+10-1} =x         (equation in problem)

       

{note: there's no reason to not simplify the equation to \sqrt{x+ 9, but the question leaves the equation that way, so I didn't simplify it either}

*I used this goal to decide which equations seemed about right, and then trying to test things out in my head

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Which expression is equivalent to 19x − 6x + 2 and why?
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<span>2 + 13x, because (19x − 6x) + 2 = 13x + 2 = 2 + 13x</span>
7 0
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Gabriele's Pie Shop sold 80 pies last month: 7/10 were apple pies and 1/10 were peach pies. How many pies were neither apple nor
AleksAgata [21]

Answer:

16 pies were neither apple nor peach.

Step-by-step explanation:

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2 years ago
Please HELP IM FALLING MATH PLEASE HELP
Ann [662]

Answer:

D

Step-by-step explanation:

32+35=67

90-67=23

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8 0
3 years ago
Use the discriminant to determine the number of solutions to the quadratic equation 3x^2+5x=-1
kari74 [83]

Answer:

Two real distinct solutions

Step-by-step explanation:

Hi there!

<u>Background of the Discriminant</u>

The discriminant b^2-4ac applies to quadratic equations when they are organised in standard form: ax^2+bx+c=0.

All quadratic equations can be solved with the quadratic formula: x = \frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}}.

When b^2-4ac is positive, it is possible to take its square root and end up with two real, distinct values of x.

When it is zero, we won't be taking the square root at all and we will end up with two real solutions that are equal, or just one solution.

When it is negative, it is impossible to take the square root and we will end up with two non-real solutions.

<u>Solving the Problem</u>

<u />3x^2+5x=-1<u />

We're given the above equation. It hasn't been organised completely in ax^2+bx+c=0, but we can change that by adding 1 to both sides to make the right side equal to 0:

3x^2+5x+1=0<u />

Now that we can identify the values of a, b and c, we can plug them into the discriminant:

D=b^2-4ac\\D=(5)^2-4(3)(1)\\D=25-4(3)(1)\\D=25-12\\D=13

Therefore, because the discriminant is positive, the equation has two real, distinct solutions.

I hope this helps!

4 0
3 years ago
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