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qaws [65]
2 years ago
15

HELP ASAP ITS TIMED

Mathematics
2 answers:
valina [46]2 years ago
4 0

Answer:

x+10=x^2+2x+1

Step-by-step explanation:

Given equation:

\sqrt{x+10}-1=x

Add 1 to both sides:

\implies \sqrt{x+10}-1+1=x+1

\implies \sqrt{x+10}=x+1

Square both sides:

\implies (\sqrt{x+10})^2=(x+1)^2

\implies \sqrt{x+10}=(x+1)(x+1)

Simplify:

\implies \sqrt{x+10}=x(x+1)+1(x+1)

\implies \sqrt{x+10}=x^2+x+x+1

\implies x+10=x^2+2x+1

Natasha_Volkova [10]2 years ago
3 0

Answer:

  x + 10 = x² + 1

(third option listed)

Step-by-step explanation:

assuming that you meant: \sqrt{x+10-1}=x  , because otherwise there would be no equivalent relationships,

(goal: isolate x on one side of the equation whilst having x on the other side of the equation also, like the equation in the question)*

   x + 10 = x² + 1

        -1            -1

   x + 10 - 1 = x²

  \sqrt{x+10-1} =\sqrt{x^2}                  [find √ of both sides to isolate x]

\sqrt{x+10-1} =x         (equation in problem)

       

{note: there's no reason to not simplify the equation to \sqrt{x+ 9, but the question leaves the equation that way, so I didn't simplify it either}

*I used this goal to decide which equations seemed about right, and then trying to test things out in my head

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