Answer:
b(b/a)^2
Step-by-step explanation:
Given that the value of the car depreciates such that its value at the end of each year is p % less than its value at the end of the previous year and that car was worth a dollars on December 31, 2010 and was worth b dollars on December 31, 2011, then
b = a - (p% × a) = a(1-p%)
b/a = 1 - p%
p% = 1 - b/a = (a-b)/a
Let the worth of the car on December 31, 2012 be c
then
c = b - (b × p%) = b(1-p%)
Let the worth of the car on December 31, 2013 be d
then
d = c - (c × p%)
d = c(1-p%)
d = b(1-p%)(1-p%)
d = b(1-p%)^2
d = b(1- (a-b)/a)^2
d = b((a-a+b)/a)^2
d = b(b/a)^2 = b^3/a^2
The car's worth on December 31, 2013 = b(b/a)^2 = b^3/a^2
Answer:
$4.50
Step-by-step explanation:
We can use the distributive property to solve this problem. 0.05(50+40) is the total sales tax. 0.05 being the percentage and 50 and 40 being the things we need to distribute 0.05 to. This becomes 2.5+2. This is 4.5.
D 18 and must be a positive number
the answer is negativepositive
Use the data to answer the following questions: 68, 63, 67, 66, 65, 87, 69, 61, 86, 82, 28
german
Rewrite given data in increasing order:
28, 61, 63, 65, 66, 67, 68, 69, 82, 86, 87
An outlier is an observation that lies an abnormal distance from other values in a random sample from a population. As you can see that number 28 lies an abnormal distance from other values.
Answer A: 28
The mean (or average) of a set of data values is the sum of all of the data values divided by the number of data values.
Answer B: 67.45
Answer C: 71.4