<span>Please help need this done now hurry 1 question below!! 25 points</span>
Step-by-step explanation:
A. y-5=-4x+4
y=-4x+4+5
y= -4x +9
(0,9)(9/4,0)
Answer: Thus when transforming from ABC to A'B'C', the lengths are scaled by a factor of 0.5 .
Step-by-step explanation:
Since the triangles are similar, the ratio of their sides are equal.
And we can count the number of blocks over which AC and A'C' is drawn and take them to be their length,
Therefore,
AC = 16
A'C'= 8
Thus when transforming from ABC to A'B'C', the lengths are scaled by a factor of 0.5 .
Measuring the tans of the angles by taking the ratio of opposite by adjacent, we get,
tanA = 
tanA'=
which means tanA= tanA'
The angles do not change.
Thus when transforming from ABC to A'B'C', the lengths are scaled by a factor of 0.5 .
The picture in the attached figure
we know that
If a tangent segment and a secant segment are drawn to a <span>circle </span><span>from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment
</span>so
DC²=BC*CA-----> CA=DC²/BC
DC=25
BC=14
CA=25²/14-----> CA=44.64
CA=BC+BA----> BA=CA-BC----> BA=44.64-14----> BA=30.64
BA is the diameter
hence
<span>the length of diameter BA is 30.64----> round to the nearest tenth---> 30.6
</span>
the answer is<span>
the length of diameter BA is 30.6</span>