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myrzilka [38]
3 years ago
15

Carl is boarding a plane. He has 2 checked bags of equal weight and a backpack that weighs 4 kg. The total weight of Carl's bagg

age is 35 kg.
Write an equation to determine the weight, w, of each of Carl's checked bags.
Mathematics
2 answers:
aniked [119]3 years ago
5 0
<span>Carl has 3 bags in total. One backpack weighs 4 kg and the rest two checking bags have the equal weight. The total weight of 3 bags is given to be 35 kg.

Let the weight of each checking bag is w kg. So we can write:

2 x (Weight of a checking bag) + Weight of Backpack = 35

Using the values, we get:

2w+ 4 = 35

Using this equation we can find the weight of each checking bag, as shown below.

2w = 31

w = 31/2

w = 15.5

Thus, the weight of each checking bag is 15.5 kg
</span>
Len [333]3 years ago
4 0

Answer: Weight of each of Carl's checked bags is 15.5 kg.

Step-by-step explanation:

Since we have given that

Number of checked bags of equal weight = 2

Weight of a backpack = 4 kg

Total weight of Carl's baggage = 35 kg

Let the weight of checked bags be 'w'.

According to question,

2w+4=35\\\\2w=35-4\\\\2w=31\\\\w=\frac{31}{2}\\\\w=15.5\ kg

Hence, Weight of each of Carl's checked bags is 15.5 kg.

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Line v passes through points (1, 12) and (10, 7). Line w is perpendicular to v. What is the slope of line w?
Firlakuza [10]

Line v passes through points (1, 12) and (10, 7). The slope of line w as improper fraction is \frac{9}{5}

<u>Solution:</u>

Given, two points are (1, 12) and (10, 7)  

We have to find the slope of a line that is perpendicular to line passing through the above given two points.

Slope of a line that pass through \left(x_{1}, y_{1}\right) \text { and }\left(x_{2}, y_{2}\right) is given as:

m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

\text { Here, in our problem, } x_{1}=1, y_{1}=12 \text { and } x_{2}=10, y_{2}=7

\text { slope } m=\frac{7-12}{10-1}=\frac{-5}{9}

So, slope of line v is \frac{-5}{9}

Since<em> </em>line w is perpendicular to v,<em> the product of their slopes equals -1</em>

\text { slope line } v \times \text { slope of line } w=-1

\frac{-5}{9} \times \text { slope of line } w=-1

\text { Slope of line } w=\frac{9}{-5} \times(-1)=\frac{9}{5}

Hence, the slope of line w as improper fraction is \frac{9}{5}

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