Ask question

Ask question

All categories

2 years ago

14

Which relation is displayed in the table? {(3,3), (3, 7), (5, 8), (9,0)} {(3,3), (7, 3), (8, 5), (0,9)} {(3,3), (3, 7), (5, 9)

, (8,0)} {(3,3), (7, 3), (5, 8), (9,0)} x y 3 7 5 8 9 0 3 3

1 answer:

bulgar [2K]2 years ago

3 0

Answer:

{(3,3), (3, 7), (5, 8), (9,0)

Step-by-step explanation:

The first number of an ordered pair is the x value and the second number is the y value.

You might be interested in

What is the relationship between the bridge strength and bridge thickness?

ivanzaharov [21]

I need more context to answer this question

7 0

2 years ago

There are 19 sweaters in a closet and some sweaters are in the dresser as well.If the total number of sweaters is 60,which of th

Y_Kistochka [10]

Answer:

A

Step-by-step explanation:

7 0

2 years ago

Jiao works as an usher at a theater. The theater has 1000 seats that are accessed through five entrances. Each guest should use

Stella [2.4K]

Answer:

The answer is "300".

Step-by-step explanation:

Please find the complete solution in the attached file.

8 0

3 years ago

Suppose an investment of $1,550 doubles in value every decade. The function f(x) = 1550(2)* give the value of the investment aft

Gala2k [10]

Answer:

$9300

Step-by-step explanation:

1550×2= 3100 3100× 3=9300

6 0

2 years ago

Evaluate the definite integral from pi/2 to put of cos theta/sqrt 1+ sin theta.

masha68 [24]

Answer:

$\textsf{B.}\quad -2(\sqrt{2}-1)$

Step-by-step explanation:

Given integral:

$\displaystyle \int^{\pi}_{\frac{\pi}{2}}\dfrac{\cos \theta}{\sqrt{1+ \sin \theta}}\:\:d\theta$

Solve by using <u>Integration by Substitution</u>

<u />

Substitute u for one of the functions of $\theta$ to give a function that's easier to integrate.

$\textsf{Let }u=1+\sin \theta$

Find the derivative of u and rewrite it so that $d \theta$ is on its own:

$\implies \dfrac{du}{d \theta}=\cos \theta$

$\implies d \theta=\dfrac{1}{\cos \theta}\:du$

Use the substitution to change the limits of the integral from $\theta$ -values to u-values:

$\textsf{When }\theta=\pi \implies u=1$

$\textsf{When }\theta=\dfrac{\pi}{2} \implies u=2$

Substitute everything into the original integral and solve:

$\begin{aligned}\displaystyle \int^{\pi}_{\frac{\pi}{2}}\dfrac{\cos \theta}{\sqrt{1+ \sin \theta}}\:\:d\theta & =\int^{1}_2}\dfrac{\cos \theta}{\sqrt{u}}\:\cdot \dfrac{1}{\cos \theta}\:\:du\\\\& =\int^{1}_{2}\dfrac{1}{\sqrt{u}} \:\:du \\\\& =\int^{1}_{2} u^{-\frac{1}{2}}\:\:du \\\\& = \left[ 2u^{\frac{1}{2}} \right]^{1}_{2}\\\\& = \left(2(1)^{\frac{1}{2}}\right)-\left(2(2)^{\frac{1}{2}}\right)\\\\& = 2-2\sqrt{2}\\\\& = -2(\sqrt{2}-1)\end{aligned}$

5 0

2 years ago