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Elden [556K]
2 years ago
7

n airplane took off from an airport and traveled at a constant rate and angle of elevation. When the airplane reached an altitud

e of 500 m, its horizontal distance from the airport was found to be 235 m. What was the angle when the airplane rose from the ground?
Mathematics
1 answer:
hram777 [196]2 years ago
7 0

The angle of the plane when it rose from the ground is 64.8 degrees

<h3>Application of trigonometry identity</h3>

Given the following parameters from the question

Altitude of the airplane H =  500m

Horizontal distance from airport "d"  = 235

Required

angle of elevation

According to the trigonometry identity

tan x = opposite/adjacent

tan x = H/d
tan x = 500/235

tan x = 2.1277

x = arctan(2.1277)

x = 64.8 degrees

The angle of the plane when it rose from the ground is 64.8 degrees

Learn more on angle of elevation here: brainly.com/question/88158

#SPJ1

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1. Find the value of x.<br><br> A. 90<br> B. 80<br> C. 60<br> D. 45
tia_tia [17]

Answer:

A 90

Step-by-step explanation:

multiple ways to prove this.

e.g. since the angle between the two lines from the center of the circle to the 2 tangent touching points is 90 degrees (that is the meaning of these 90 degrees here as the angle of the circle segment defined by the 2 tangent touching points and the circle center), the tangents have the same "behavior" as tan and cot = the tangents at the norm circle at 0 and 90 degrees. they hit each other outside of the circle again at 90 degrees.

another way

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the Hypotenuse of each triangle is cutting the 90 degree angle of the circle segment exactly in half (due to the symmetry principle). so the angle between radius side and Hypotenuse is 90/2 = 45 degrees.

that means also the angle of such a right triangle at the tangent crossing point is 45 degrees (as the sum of all angles in a triangle must be 180, we have the remainder of 180 - 90 - 45 = 45 degrees).

the angles of both right triangles at that point are the same, and so we can add 45+45 = 90 degrees for the total angle at the tangent crossing point.

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3 years ago
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Ghella [55]

This is similar to the other question you posted. Follow the same steps as before.

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Did you follow?

6 0
3 years ago
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