n airplane took off from an airport and traveled at a constant rate and angle of elevation. When the airplane reached an altitud

Question

2 years ago

7

e of 500 m, its horizontal distance from the airport was found to be 235 m. What was the angle when the airplane rose from the ground?

1 answer:

hram777 [196] · Answer 1 · 2023-05-06T11:04:52+03:00

The angle of the plane when it rose from the ground is 64.8 degrees

<h3>Application of trigonometry identity</h3>

Given the following parameters from the question

Altitude of the airplane H = 500m

Horizontal distance from airport "d" = 235

Required

angle of elevation

According to the trigonometry identity

tan x = opposite/adjacent

tan x = H/d
tan x = 500/235

tan x = 2.1277

x = arctan(2.1277)

x = 64.8 degrees

The angle of the plane when it rose from the ground is 64.8 degrees

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