So the question ask to find the displacement vector and the distance from the submarine to the boat. Base on my calculation the displacement value of the given data you give is <(5-3),(1-4)(-5-0)>. I hope you are satisfied with my answer and feel free to ask for more
√4 =2
√8= 2<span>√<span>2
</span></span>√10=√10 as (Decimal: 3.162278)
√15=√15 as (Decimal: 3.872983)
√35=√35 as (Decimal: 5.91608)
Answer:
about 2949 feet
Step-by-step explanation:
The geometry of the situation can be modeled by a right triangle. The height of the cliff can be taken to be the side opposite the given angle, and the distance to the coyote will be the side adjacent to the given angle. The relation between these values is the trig function ...
Tan = Opposite/Adjacent
__
<h3>setup</h3>
Filling in the known values, we have ...
tan(6°) = (310 ft)/(distance to coyote)
<h3>solution</h3>
Multiplying by (distance to coyote)/tan(6°) gives ...
distance to coyote = (310 ft)/tan(6°) ≈ 310/0.105104 ft
distance to coyote ≈ 2949.453 ft
The coyote is about 2949 feet from the base of the cliff.
Hanna bought 85 candies and ate 20 of them. How many candies are left?
Answer:
Im answering in a sec
First is 0
X 4 Y 0
second is 2
X 6 Y 2
Third is 4
X 8 Y 4
PLS mark brainiest if correct
Step-by-step explanation: