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vfiekz [6]
3 years ago
11

Complete the square to form a true equation; x^2-3/4x+__ = (x-__)^2

Mathematics
2 answers:
timofeeve [1]3 years ago
6 0

Step-by-step explanation:

(x^2-3/4x+y^2)=(x-y)2

(x-3/4*1/2)2

(x-3/8)(x-3/8)

(x^2-3x/8-3x/8+9/64)

(x^2-6x/8+9/64)

(x-3/8)2

Free_Kalibri [48]3 years ago
4 0

172273-3-$=$==8399993939384888884-%"%/=%=%8%

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-The graph measures by twos. To get the area of the rectangle get the base times height of it. That would be 16x16=256.

-Get base (8) times height (6) of triangle 1 then divide by 2, remember to count the squares by 2 for finding all areas. The formula would be 1/2(b)(h) because dividing by 2 is the same as multiplying times 1/2. Plug it in and     (8)(6)=48 then divide by 2 which equals 24.

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-Same formula for triangle 3. Plugged in is (12)(16)=192 divide by 2 and it equals 96.

-To find the area of the trapezoid get your rectangle area (256) and subtract all the triangle areas. So 256 - 6 - 16 - 96 = 120.

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