Answer:
{x = 7
, y = 4
Step-by-step explanation using elimination:
Solve the following system:
{5 (2 x - y) = 7 x + 1 | (equation 1)
{3 (3 x + y) = 5 (12 + x - y) | (equation 2)
Express the system in standard form:
{3 x - 5 y = 1 | (equation 1)
{4 x + 8 y = 60 | (equation 2)
Swap equation 1 with equation 2:
{4 x + 8 y = 60 | (equation 1)
{3 x - 5 y = 1 | (equation 2)
Subtract 3/4 × (equation 1) from equation 2:
{4 x + 8 y = 60 | (equation 1)
{0 x - 11 y = -44 | (equation 2)
Divide equation 1 by 4:
{x + 2 y = 15 | (equation 1)
{0 x - 11 y = -44 | (equation 2)
Divide equation 2 by -11:
{x + 2 y = 15 | (equation 1)
{0 x+y = 4 | (equation 2)
Subtract 2 × (equation 2) from equation 1:
{x+0 y = 7 | (equation 1)
{0 x+y = 4 | (equation 2)
Collect results:
Answer: {x = 7
, y = 4
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