We know that
sin²x+cos²x=1
so
clear cos x
cos x=(+/-)√[1-sin²x]
in this problem
<span>Angle 0 is in quadrant 1 -----> cos o and sin o are positive
</span>sin o=2/5
cos x=√[1-(2/5)²]----> cos o=√[1-4/25]----> cos o=√[21/25]---> cos o=√21/5
the answer is
cos o=√21/5
Sadly, after giving all the necessary data, you forgot to ask the question.
Here are some general considerations that jump out when we play with
that data:
<em>For the first object:</em>
The object's weight is (mass) x (gravity) = 2 x 9.8 = 19.6 newtons
The force needed to lift it at a steady speed is 19.6 newtons.
The potential energy it gains every time it rises 1 meter is 19.6 joules.
If it's rising at 2 meters per second, then it's gaining 39.2 joules of
potential energy per second.
The machine that's lifting it is providing 39.2 watts of lifting power.
The object's kinetic energy is 1/2 (mass) (speed)² = 1/2(2)(4) = 4 joules.
<em>For the second object:</em>
The object's weight is (mass) x (gravity) = 4 x 9.8 = 39.2 newtons
The force needed to lift it at a steady speed is 39.2 newtons.
The potential energy it gains every time it rises 1 meter is 39.2 joules.
If it's rising at 3 meters per second, then it's gaining 117.6 joules of
potential energy per second.
The machine that's lifting it is providing 117.6 watts of lifting power.
The object's kinetic energy is 1/2 (mass) (speed)² = 1/2(4)(9) = 18 joules.
If you go back and find out what the question is, there's a good chance that
you might find the answer here, or something that can lead you to it.
Answer:
A≅407.34 au (area units)
Step-by-step explanation:
we must find the area generated by equations a., b., and c. To do this we must graph and the areas and determine their points to evaluate
As seen in the graphs (1, 2) we have the area generated by equations a. b. and the limits within which the area should be evaluated are those determined by c.
Finally we find A (view graph 3)
Answer:
- 16
Step-by-step explanation:
Evaluate f(2) by substituting x = 2 into f(x) , that is
f(2) = 3(2) - 3 = 6 - 3 = 3
Evaluate g(- 1) by substituting x = - 1 into g(x) , that is
g(- 1) = 8 - (- 1)² = 8 - 1 = 7
Thus
4f(2) - 4g(- 1)
= 4(3) - 4(7)
= 12 - 28
= - 16
