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3 years ago

What the heck do i do with this

Mathematics

2 answers:

Ad libitum [116K]3 years ago

7 0

Use the law of cosines to find a: $a^2=b^2+c^2-2bc (cos(A))$

So to use the given numbers you get: $a^2=27^2+45^2-2(27)(45)(cos(53))$

Which would come out to equal about 35.94

so a=35.9

Marizza181 [45]3 years ago

6 0

Answer:

Eat it

Step-by-step explanation:

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I need help can I don’t know how to do this problem

Elden [556K]

Answer:

a ^ (1/12)

Step-by-step explanation:

a ^ (1/3)

---------------

a ^ (1/4)

We know that b^ c / b^ d = b ^ (c-d)

a^ (1/3 - 1/4)

getting a common denominator

1/3 *4/4 - 1/4*3/3 = 4/12 - 3/12

a^ (4/12 - 3/12)

a ^ (1/12)

7 0

3 years ago

En una caja grande hay 9 cajas dentro de cada una de estas cajas hay 5 cajas, dentro de estas hay 3 cajas. ¿Cuántas cajas hay en

Kazeer [188]

Answer:

34 cajas

MANTENTE SALVAJE

8 0

3 years ago

Read 2 more answers

Find the solution of the differential equation that satisfies the given initial condition. dy/dx=x/y , y(0)=-1

Charra [1.4K]

Separating variables, we have

$\dfrac{dy}{dx} = \dfrac xy \implies y\,dy = x\,dx$

Integrate both sides.

$\displaystyle \int y\,dy = \int x\,dx$

$\dfrac12 y^2 = \dfrac12 x^2 + C$

Given that $y(0)=-1$ , we find

$\dfrac12 (-1)^2 = \dfrac12 0^2 + C \implies C = \dfrac12$

Then the particular solution is

$\dfrac12 y^2 = \dfrac12 x^2 + \dfrac12$

$y^2 = x^2 + 1$

$y = \pm\sqrt{x^2 + 1}$

and because $y(0)=-1$ , we take the negative solution to accommodate this initial value.

$\boxed{y(x) = -\sqrt{x^2+1}}$

7 0

2 years ago

Determine if is y=3x^2+2x-3 linear, quadratic, or exponential.

podryga [215]

Answer:

it is quadratic

Step-by-step explanation:

a quadratic graph should look like this

MARK BRAINIEST IF IT HELPS

6 0

2 years ago

What is the length of c in inches

crimeas [40]

Answer:

$\sqrt{500}$ inches

Step-by-step explanation:

a^2+b^2=c^2

10^2+20^2=c^2

100+400=c^2

c^2=500

$\sqrt{500}$

4 0

3 years ago