The domain of a function is the set of values for which the function is defined; i.e. the function outputs a value for an input from the domain. That means that we must be able to plug in numbers for x and get numbers from y.
We can't take the square root of negative numbers (ignoring imaginary numbers), so that means we can take the square root of any non-negative number; i.e. we can take the square root of zero, and any positive number.
Therefore, any function that can take in values of x that are zero or more than zero has the same domain as the given function. So

is a function that has the same domain as

.
The solution to the problem is as follows:
Given: 2.5 lb
Asked: 2.5 lb -----> kg
Answer:
2.5 lb * ( 1 kg/2.2 lb) = 1.1 kg
Therefore, the weight of the book in kg is 1.1 kg.
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Hello!
First you can distribute the 3
4 + 6r + 6s + 3r
Then you combine like terms
4 + 9r + 6s
The answer is 9r + 6s + 4
Hope this helps!
Answer:
y = 0
Step-by-step explanation:
It is always a good idea to look at the question and make some observations about it. Here, you might observe ...
- all of the bases are powers of 3: 243 = 3^5; 9 = 3^2
- y is a factor of every exponent
The latter observation is important, because it means that when y=0, every exponential expression has a value of 1. Hence y = 0 is a solution.
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To solve the equation, you can write it in terms of powers of 3.
(3^5)^(-y) = (3^-5)^(3y)·(3^2)^(-2y)
3^(-5y) = 3^(-15y)·3^(-4y)
3^(-5y) = 3^(-19y)
-5y = -19y . . . . . . . . equating exponents; equivalent to taking log base 3
14y = 0 . . . . . . . . . . add 19y
y = 0 . . . . . . . . . . . one solution
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The rules of exponents we used are ...
(a^b)(a^c) = a^(b+c)
(a^b)^c = a^(bc)
1/a^b = a^-b