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Alenkasestr [34]
4 years ago
14

Pls help me and show work

Mathematics
1 answer:
padilas [110]4 years ago
6 0

Answer:

Step-by-step explanation:

a batch requires 3 cups of flour, so a half batch requires a half of 3 cups of flour,

which mean a 1/2 batch needed <u>1 and 1/2 cups of flour</u><u>.</u>

so a cup of flour can make ??? batch of bread:

3 cup = 1 batch

4 cup = ? batch

so the answer is 4/3 batch or <u>1 and 1/3 batch of bread</u> for 4 cups of flour

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[Function Composition] could someone help me with this answers or show work either is fine
zavuch27 [327]

Answer:

21

Step-by-step explanation:

Given the following expressions

f(x) = x³-2x

g(x) =-x-2

We are to find (fog)(-5)

fog = f(g(x))

f(g(x)) = f(-x-2)

Replace x with -x-2 in f(x)

f(-x-2) = (-x-2)³-2(-x-2)

f(-x-2) = (-x-2)³+2x+4

fog = (-x-2)³+2x+4

Substitute x = -5 into the result

fog(-5) = (-x-2)³+2x+4

fog(-5) = (-(-5)-2)³+2(-5)+4

fog(-5) = (5-2)³-10+4

fog(-5) = 3³-6

fog(-5) = 27-6

fog(-5) = 21

Hence the required result of the composite function is 21

8 0
3 years ago
Find the indicated nth partial sum of the arithmetic sequence.<br> −7, −3, 1, 5, . . ., n = 30
TiliK225 [7]

Step-by-step explanation:

Given the Arithmetic sequence

-7, -3, 1, 5, . . .

An arithmetic sequence has a constant difference d and is defined by

a_n=a_1+\left(n-1\right)d

\mathrm{Compute\:the\:differences\:of\:all\:the\:adjacent\:terms}:\quad \:d=a_{n+1}-a_n

-3-\left(-7\right)=4,\:\quad \:1-\left(-3\right)=4

\mathrm{The\:difference\:between\:all\:of\:the\:adjacent\:terms\:is\:the\:same\:and\:equal\:to}

d=4

\mathrm{The\:first\:element\:of\:the\:sequence\:is}

a_1=-7

as

a_n=a_1+\left(n-1\right)d

\mathrm{Therefore,\:the\:}n\mathrm{th\:term\:is\:computed\:by}\:

a_n=4\left(n-1\right)-7           ∵ d=4

\mathrm{Arithmetic\:sequence\:sum\:formula:}

n\left(a_1+\frac{d\left(n-1\right)}{2}\right)

\mathrm{Plug\:in\:the\:values:}

n=30,\:\space a_1=-7,\:\spaced=4

=30\left(-7+\frac{4\left(30-1\right)}{2}\right)

=30\left(58-7\right)     ∵  \frac{4\left(30-1\right)}{2}=58

=30\cdot \:51

=1530           ∵  \mathrm{Multiply\:the\:numbers:}\:30\cdot \:51=1530

Therefore, the indicated nth partial sum of the arithmetic sequence is 1530.

ANOTHER METHOD

as

a_n=4\left(n-1\right)-7

n = 30

\sum _{n=1}^{30}\:4\left(n-1\right)-7

=\sum _{n=1}^{30}4n-11

\mathrm{Apply\:the\:Sum\:Rule}:\quad \sum a_n+b_n=\sum a_n+\sum b_n

=\sum _{n=1}^{30}4n-\sum _{n=1}^{30}11

as

\sum _{n=1}^{30}4n=1860

and

\sum _{n=1}^{30}11=330

so

=1860-330

=1530

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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y - 2 = -1/4x + 1

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