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Olegator [25]
2 years ago
12

Three objects have velocities that vary with time

Physics
2 answers:
olganol [36]2 years ago
8 0

Answer:

See below ~

Explanation:

Question 21 :

⇒ v = u + at

⇒ v = 5 + 1.3 (2)

⇒ v = 5 + 2.6

⇒ v = 7.6 m/s

=============================================================

Question 22 : At t = 3

<u>Subpart (a)</u>

⇒ Object 1 : v = 2 + 3(3) = 11 m/s

⇒ Object 2 : v = -8 - 4(3) = -20 m/s

⇒ Object 3 : v = 1 - 5(3) = -14 m/s

⇒ Hence, their velocities are in the order : Object 2 < Object 3 < Object 1

<u>Subpart (b)</u>

⇒ Object 1 : v = | 2 + 3(3) | = 11 m/s

⇒ Object 2 : v = | -8 - 4(3) | = 20 m/s

⇒ Object 3 : v = | 1 - 5(3) | = 14 m/s

⇒ Hence, their speeds are in the order : Object 1 < Object 3 < Object 2

Solnce55 [7]2 years ago
7 0

#21

  • initial velocity=u=5m/s
  • Time=t=2s
  • Acceleration=a=1.3m/s²

According to first equation of kinematics

  • v=u+at
  • v=5+1.3(2)
  • v=5+2.6
  • v=7.6m/s

#22

#a

  • v1=2+3(3)=2+9=11m/s
  • v2=-8-4(3)=-20m/s
  • v3=1-5(3)=-14m/s

The order is

  • v2<V3<v1

#b

for speed find absolute velocity

  • S1=|11|=11m/s
  • S2=|-20|=20m/s
  • S3=|-14|=14m/s

So order is

S1<S3<S2

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