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Sidana [21]
3 years ago
12

A laser (electromagnetic wave) has the maximum electric field strength of 1.0x1011 V/m. What is the force the laser applies on a

mirror (totally reflective) of 5.0 mm2 area? A. 2.76 x105N B. 1.21 x106N C. 1.94 x106N D.4.43 x105 N E. 7.82 x104N
Physics
1 answer:
Alex777 [14]3 years ago
8 0

Answer:

The correct option is  D

Explanation:

From the question we are told that

  The maximum electric field strength is  E = 1.0 *10^{11} \  V/m

   The  area is  A = 5.0 \ mm^2  = 5.0 *10^{-6} \  m^2

Generally the force the laser applies is mathematically represented as

       F = \epsilon_o * E ^2 * A

Here  \epsilon_o = 8.85*10^{-12} C/(V \cdot m)

      F =  8.85*10^{-12}  * (1.0 *10^{11}) ^2 * 5.00*10^{-6 }

=>   F =  4.43 *10^{5} \ N

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What are the seven different forms of energy? Give an example of each.
wel

Answer:

Form of energy: Example

1. Light energy: Electromagnetic radiation

2. Nuclear energy: Nuclear fission

3. Chemical energy: Energy stored in plant matter

4. Electrical energy: Lightning

5. Thermal energy: A hot surface

6. Sound energy: A tuning fork

7. Solar energy: Energy from the Sun

8. Mechanical energy: A moving vehicle

5 0
3 years ago
Emily holds a banana of mass m over the edge of a bridge of height h. She drops the banana and it falls to the river below. Use
bearhunter [10]

Answer:

The mass of the banana is m and it is at height h.

Applying the Law of Conservation of Energy

              Total Energy before fall = Total Energy after fall

                                E_{i}  = E_{f}

Here, total energy is the sum of kinetic energy and potential energy

K.E_{i} + P.E_{i} = K.E_{f} + P.E_{f}       (a)

When banana is at height h, it has

                 K.E_{i} = 0    and    P.E_{i} = mgh          

and when it reaches the river, it has

       K.E_{f}  = 1/2mv^{2}    and   P.E_{f}  = 0

Putting the values in equation (a)

                              0 + mgh = 1/2mv^{2} + 0

                                      mgh = 1/2mv^{2}

<em>cutting 'm' from both sides</em>

<em>                                           </em>gh = 1/2v^{2}

                                          v = \sqrt{2gh}

Hence, the velocity of banana before hitting the water is

                                          v = \sqrt{2gh}

5 0
3 years ago
Galaxies are separated by?
Inessa [10]
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8 0
3 years ago
Read 2 more answers
How many electrons must be remowel from an electricaly Nurutral Silvor Coin to five it a charge of 3.2 NC ?
kakasveta [241]

Answer:

 #_electrons = 2 10¹⁰ electrons

Explanation:

For this exercise we can use a direct rule of three proportions rule. If an electron has a charge of 1.6 10⁻¹⁹ C how many electrons have a charge of 3.2 10⁻⁹ C

          #_electrons = 3.2 10⁻⁹ ( \frac{1}{1.6 \ 10^{-19}})

          #_electrons = 2 10¹⁰ electrons

7 0
3 years ago
A proton is released from rest at the origin in a uniform electric field that is directed in the positive xx direction with magn
elena-s [515]

Answer:

The change in potential energy is  \Delta  PE =  -  3.8*10^{-16} \ J

Explanation:

From the question we are told that

     The  magnitude of the uniform electric field  is  E =  950 \ N/C

      The  distance traveled by the electron is  x =  2.50 \ m

Generally the force on this electron is  mathematically represented as

     F =  qE

Where F is the force and  q is the charge on the electron which is  a constant value of  q =  1.60*10^{-19} \ C

    Thus  

      F  =  950  * 1.60 **10^{-19}

      F  = 1.52 *10^{-16} \ N

Generally the work energy theorem can be mathematically represented as

          W =  \Delta  KE

Where W is the workdone on the electron by the  Electric field and  \Delta  KE  is the change in kinetic energy

Also  workdone on the electron can also  be represented as

        W =  F* x  *cos(  \theta )

Where  \theta  =  0 ^o considering that the movement of the electron is along the x-axis  

        So

             \Delta  KE  =  F  * x  cos  (0)

substituting values

         \Delta  KE  =  1.52 *10^{-16}  * 2.50   cos  (0)

          \Delta  KE   =  3.8*10^{-16} J

Now From the law of energy conservation

       \Delta PE  =  -  \Delta  KE

Where \Delta  PE is the change  in  potential energy  

Thus  

        \Delta  PE =  -  3.8*10^{-16} \ J

               

7 0
3 years ago
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