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Sveta_85 [38]
3 years ago
6

7. How many forces are acting on this object? * Fnorm Ffrict Fapp Fgray Å

Physics
1 answer:
faust18 [17]3 years ago
4 0

Answer:

4

Explanation:

As you can see in the free body diagram there are 4 forces acting on the body.

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A wire of Nichrome (a nickel-chromium-iron alloy commonly used in heating elements) is 1.3 m long and 1.6 mm2 in cross-sectional
fredd [130]

Answer: 1.3 *10^6 Ω*m

Explanation: In order to explain this problem we have to use the following expression for the resistence:

R=L/(σ*A) where L and A are the length and teh area for the wire, respectively. σ is the conductivity of teh Nichrome.

Then, from mteh OHM law we have V=R*I so R=V/I=2/3.2=0.625 Ω

Finally we have:

σ=L/(R*A)=1.3/(0.625*1.6*10^-6)=1.3*10^6 Ω*m

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3 years ago
Which type of environmental science career involves collecting information about how human events impact the environment?
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C. environmental engineer
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The liquid pressure exerted in one direction only​
Wewaii [24]
The pressure exerted by a liquid on an object increases as we go more deep into the liquid and this pressure is called as hydro static pressure . if we consider a part of the static fluid then all the horizontal forces will cancel out while the vertical forces will add vectorilly and due to which a pressure difference is created . so as we go more deep the pressure increase .

Now pressure is a scalar so it does not depend on direction but when two objects are on the same level with respect to a reference level then the pressure exerted on them by fluid is always the same . hope this helps
8 0
3 years ago
Can someone answer these questions
Aleks04 [339]

Answer:

1. Following the recoil principle, rockets use combustion (a controlled explosion) to work against earth's gravitational attraction.

2. A force is a push or a pull that acts upon an object as a results of its interaction with another object. ... These two forces are called action and reaction forces and are the subject of Newton's third law of motion. Formally stated, Newton's third law is: For every action, there is an equal and opposite reaction.

(via physicsclassroom.com)

3. The combustion throws out material with very high momentum and is, physically speaking, the action. In reaction to that that, the rocket moves away from it (upward when in starts and has the action underneath it)

4. To show the world that commercial manned space missions are safely possible. Some may also like the fact that the US can now do, or rather order, manned flights into space without the help of the russian space agency (Roskosmos).

5. Robert Behnken and Douglas Hurley

6. The international space station (ISS)

7. Yes, Stage 1 of the rocket landed on the drone ship. The crew opened the hatch to enter the space station after 21 hours and 39 minutes after the launch from Cape Canaveral.

8. To have private contractors such as SpaceX actively in the field, there are now more interest groups that participate in space travel. And they can interact with other companies as well.

Also, due to Musks dream and efforts of SpaceX, space travel seems to get a lot cheaper.

That might indeed open the way back to the moon and further to the Mars for human space flight.

Governments such as the US planned on such things for decades, but changed plans ever since, and routinely changed leadership and the opinion on what's important.

Now Spaceflights can become less politically motivated and more commercially. That seems to be a more stable way over long periods of time.

(wrote most of it for you myself, even tough I'm not a native English speaker. would really appreciate the brainliest if you appreciate the work)

5 0
3 years ago
Read 2 more answers
A disk of mass M and radius R rotates at angular velocity ω0. Another disk of mass M and radius r is dropped on top of the rotat
AleksandrR [38]

Answer:

\omega = \frac{(R^2\omega_o}{(R^2 + r^2)}

Explanation:

As we know that there is no external torque on the system of two disc

then the angular momentum of the system will remains conserved

So we will have

L_i = L_f

now we have

L_i = (\frac{1}{2}MR^2)\omega_o

also we have

L_f = (\frac{1}{2}MR^2 + \frac{1}{2}Mr^2)\omega

now from above equation we have

(\frac{1}{2}MR^2)\omega_o  = (\frac{1}{2}MR^2 + \frac{1}{2}Mr^2)\omega

now we have

\omega = \frac{MR^2\omega_o}{(MR^2 + Mr^2)}

\omega = \frac{(R^2\omega_o}{(R^2 + r^2)}

6 0
3 years ago
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