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Nikitich [7]
3 years ago
12

Complete this sentence. The melting point of a sample will ____________ when the size of the sample increases. (3 points)

Physics
2 answers:
ohaa [14]3 years ago
8 0

Answer:

Answer is Option 1. decreases

stepladder [879]3 years ago
8 0
It will decrease because it will take more to melt.
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Someone help pleaseeee
SSSSS [86.1K]

Answer:

C. resonating

an object being forced to vibrate at its natural frequency creates resonance

5 0
3 years ago
A uniform steel girder of weight 22KN and of length 12m is lifted off the ground at one end by means of a crane. When the raised
Keith_Richards [23]

Answer:

Explanation:

For free body diagram see attached sheet .

W is weight of steel girder acting at the middle point of its length . T is tension in the cable .

OB = √ ( 12² - 2² )

= 11.83 m .

OC = 11.83 / 2 = 5.915 m

Taking moment of tension T and weight W about point O

W x OC = T x OB

22 x 5.915 = T x 11.83

T = 22 x 5.915 / 11.83

= 11 kN

Considering forces acting in vertical direction and equating forces in opposite direction

T + R = W

R = W - T

= 22 - 11 = 11 KN

So force of grinder on the ground = R

= 11 KN.

8 0
3 years ago
The capacitor in the figure (Figure 1) is initially uncharged. The switch is closed at t=0.
fomenos
Immediately after the switch is closed, the capacitor acts like a short circuit for a very small time. We can calculate the currents through each resistor by first calculating the total resistance:

Req = 1/(1/3+1/6) + 8 = 1/(3/6) + 8 = 2 + 8 = 10 ohms.
IR1 = E / Req = 42 / 10 = 4.2 A.
VR2 = VR3 = E * R23 / Req = 42 * 2 / 10 = 8.4 V
IR2 = VR2 / R2 = 8.4 / 6 = 1.4 A.
IR3 = VR3 / R3 = 8.4 / 3 = 2.8 A.

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
3 0
3 years ago
A uniform solid ball rolls smoothly along a floor, then up a ramp inclined at 33.0°. It momentarily stops when it has rolled 1.7
galben [10]

Answer:

v = 3.6 m/s

Explanation:

given,

Inclination of the ramp, θ = 33⁰

Distance of the rope, d = 1.70 m

initial speed = ?

using conservation of energy

\dfrac{1}{2}mv^2 + \dfrac{1}{2}I_{com}\omega^2 = m g h

h = d sinθ  

h = 1.7 x sin 33° = 0.926 m

moment of inertia of the solid ball

I_{com}= \dfrac{2}{5}MR^2  

we know, v = r ω

\dfrac{1}{2}mv^2 + \dfrac{1}{2}\dfrac{2}{5}mR^2\times \dfrac{v^2}{R^2}= m g h

\dfrac{1}{2}mv^2 + \dfrac{1}{5}mv^2 = mgh

gh= \dfrac{7}{10}v^2

v = \sqrt{\dfrac{10}{7}gh}

v = \sqrt{\dfrac{10}{7}\times 9.8\times 0.926}

v = 3.6 m/s

Hence, initial speed of the solid ball = 3.6 m/s

8 0
3 years ago
Your calculated density of aluminum is d = 2.76 g/cm3. Aluminum’s accepted density is 2.70 g/cm3. Without writing the "%" sign,
Rina8888 [55]

Answer:T he percentage error up to two decimal places is 2.22 %.

Explanation:

To calculate the percentage error, we use the equation:

\%\text{ error}=\frac{|\text{Experimental value - Accepted value}|}{\text{Accepted value}}\times 100

We are given:

Experimental value of density= 2.76g/cm^3

Accepted value of density = 2.70g/cm^3

\%\text{ error}=\frac{[{2.76 - 2.70}|}{2.70}\times 100=2.22%

Hence, the percentage error is 2.22 %.

3 0
3 years ago
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