1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lara [203]
3 years ago
11

a circuit is connected to 8 volt battery and it has 2 amperes of current flowing through the wires.What is the resistance of the

circuit
Physics
1 answer:
guajiro [1.7K]3 years ago
4 0

Answer:

4 ohms

Explanation:

Current = Voltage/resistance

2 = 8/R

2R = 8

R = 4

You might be interested in
How would you write the number 6,500,000,000 in scientific notation?
photoshop1234 [79]
Scientific form = 6.5 x 109.
8 0
3 years ago
"2.40 A pressure of 4 × 106N/m2 is applied to a body of water that initially filled a 4300 cm3 volume. Estimate its volume after
wel

Answer:Final volume after pressure is applied=4,292cm3

Explanation:

Using the bulk modulus formulae

We have that The bulk modulus of waTer is given as  

K =-V dP/dV

Where  K, the bulk modulus of water = 2.15 x 10^9N/m^2

2.15 x 10^9N/m^2= - 4,300 x  4 × 106N/m2 / dV

dV = - 4,300 x  4 × 10^6N/m^2/ 2.15 x 10^9N/m^2

dV (change in volume)= -8.000cm^3

Final volume after pressure is applied,

V= V+ dV

V= 4300cm3 + (-8.000cm3)

=4300cm3 - 8.000cm3

Final Volume, V =4,292cm3

3 0
3 years ago
A) explain how the data matches each line on the graph (give name and line letter for each)
stepladder [879]
The answer you have is right good job 12
3 0
2 years ago
What is the momentum of a 200 kg truck travelling at 20 m/s?
geniusboy [140]

Answer:

p = 4000 kg-m/s

Explanation:

Given that,

The mass of a truck, m = 200 kg

Speed of the truck, v = 20 m/s

We need to find the momentum of the truck. The formula for momentum is given by :

p = mv

so,

p=200\times 20\\\\p=4000\ kg-m/s

So, the momentum of the truck is equal to 4000 kg-m/s.

8 0
3 years ago
What kind of water temperature lowers the dissolved oxygen
ehidna [41]
<h3>Answer</h3>

At a high temperature above 20° oxygen solubility starts to decrease.

<h3>Explanation</h3>

Oxygen, O2 is a very essential component of water as we can see in its chemical formula h2O.

The solubility of oxygen decreases as temperature increases. This means that warmer water will have less dissolved oxygen than does cooler water.

<h3>Other factors that affects oxygen solubility in water</h3>

Salt levels

higher the salt levels in water, lower will be oxygen in it.

Pressure

Water at lower altitudes can hold more dissolved oxygen than water at higher altitudes because dissolved oxygen will increase as pressure increases.

5 0
3 years ago
Read 2 more answers
Other questions:
  • A motorcycle has a magnet attached to the rim of its front wheel. The front tire has a diameter of 60 cm. A magnetic pickup is a
    15·1 answer
  • A chemical hazard symbol means you should not inhale fumes or let the chemicals contact your skin.
    9·1 answer
  • A 5 kilogram block is dropped from a height of 3 meters and falls straight to the ground. What is the work done by the force of
    5·1 answer
  • how do i find out the maximum speed and things? also, if you can give the answer and tell me why that would be amazing!!
    8·1 answer
  • Which of the following could describe the velocity of an object?
    12·2 answers
  • Brainliest for correct answer! :)
    14·1 answer
  • Three cars (car F, car G, and car H) are moving with the same velocity, and slam on the brakes. The most massive car is car F, a
    7·1 answer
  • What does it say about the application of Newtons second law of motion in football
    5·1 answer
  • One component of a magnetic has a magnitude of 0.045T and points along the +r axis, while the other component has a magnitude of
    5·1 answer
  • falling parachutist you bail out of the helicopter of example 3 and pull the ripcord of your parachute. now in eq. (3), so your
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!