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Thepotemich [5.8K]

2 years ago

15

Suppose f (x) = x^3 - 1 . Find the graph of 5f (x)

1 answer:

Harlamova29_29 [7]2 years ago

5 0

Answer:

Graph 1

Step-by-step explanation:

If f(x) =x³- 1

Then 5f (x) 5(x³-1) = 5x³-5

See attached

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If n represents a number, then write an expression for three times the difference of the number and six increased by four times

Elenna [48]

$3(n-6)+4n$

8 0

2 years ago

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A normal distribution has a mean 20 and standard deviation 5. What is the z score that corresponds to the value x=222

sashaice [31]

Answer: The z score that corresponds to the value x=22 is 0.4 .

Step-by-step explanation:

Given : A normal distribution has a mean 20 and standard deviation 5.

i.e. $\mu=20$

$\sigma=5$

Let x be the random selected variable.

We know that to find the z-score corresponds to the value x is given by :-

$z=\dfrac{x-\mu}{\sigma}$

For x = 22, we have

$z=\dfrac{22-20}{5}=\dfrac{2}{5}\\\\\Rightarrow\ z=0.4$

Hence, the z score that corresponds to the value x=22 is 0.4

5 0

2 years ago

Find the slope of the line containing the pair of points (4,8), (9,-4)

Papessa [141]

The given points are (4,8) & (9,-4)

slope of a line = <u>Y2 - Y1</u>

X2 - X1

====> <u>(-4) - 8</u> = <u>-12</u>

9 - 4 5

6 0

3 years ago

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Consider the table for the exponential function, LaTeX: p\left(x\right)=2^xp ( x ) = 2 x, shown below. Calculate the Average Rat

Mice21 [21]

Answer:

15

Step-by-step explanation:

To find the average rate if change of the exponential function between the interval [2, 6], use the formula, $m = \frac{p(b) - p(a)}{b - a}$

Where,

$a = 2, p(2) = 4$

$b = 6, p(6) = 64$

Plug in the above values into the formula:

$m = \frac{64 - 4}{6 - 2}$

$m = \frac{60}{4}$

$m = 15$

Average rate of change is 15

3 0

2 years ago

Need ASAP Now!! please help with answer!

puteri [66]

Answer:

$y = 1500 * 1.09^t$

Step-by-step explanation:

$\text{It should be clear that the rate of change is non-linear}$ $\text{, meaning that we can express the function in the following manner}$

$\text{y = a * b^t, where a is the initial value and b is the rate of change and t is how}$ $y = a * b^t,$ $\text{where a is the initial value and b is the rate of change and t is how many years.}$

$\text{Well, year 0 is the rate of change so we can say that a = 1500}$

$\text{Next, we divide any two consecutive year balances to find our rate of change:}$

$1635/1500 = 1.09$

$\text{Therefore, our equation looks like this:}$

$y = 1500 * 1.09^t$

8 0

1 year ago

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