Answer:
3x+y=8 and 3x+y=9
Step-by-step explanation:
Assume these two equations:
a1x+b1y+c1=0
a2x+b2y+c2=0
If (a1/a2) = (b1/b2) ≠ (c1/c2) than those two would have no solution.
In these case, take a look at the last option:
Re-write 'em as a standard form:
So (a1/a2) = (b1/b2) ≠ (c1/c2) is true here:
And they do not have any collision point
Answer:
g(q) = 5/8q
Step-by-step explanation:
-7q + 12r = 3q - 4r
Add 4r to each side
-7q + 12r+4r = 3q - 4r+4r
-7q +16r = 3q
Add 7q to each side
-7q+7q +16r = 3q+7q
16r = 10q
Divide each side by 16
16r/16 = 10q/16
r = 5q/8
g(q) = 5/8q
of the odd number it would be 3/6 in other words 1/2 Step-by-step explanation:
Hello from MrBillDoesMath!
Answer:
m^2 + 11m - 11, which is the first choice
Discussion:
6m + (m-2)(m+7) +3 =
6m + (m^2 + 7m - 2m -14) + 3 =
(6m + 7m - 2m) + m^2 + (-14 + 3) = combine similar terms
11m + m^2 -11 =
m^2 + 11m - 11
which is the first choice
Thank you,
MrB
