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Mekhanik [1.2K]
2 years ago
14

Please fix the question and help me do it the right way

Mathematics
1 answer:
Anestetic [448]2 years ago
3 0

the last step is wrong because we multiply the powers in this case we do not subtract them.

we use power subtract in division.

we use power multiplication when we raise to power and the root is power like square root of x

\sqrt{x}  =  {x}^{ \frac{1}{2} }

so

\sqrt[3]{x}  =  {x}^{ \frac{1}{3} }

in our case

this step is wrong

2x \times  \sqrt[3]{ \frac{2}{y}  \times  \frac{y}{y} }

it should be

2 x \times  \sqrt[3]{ \frac{2}{y}  \times  \frac{ {y}^{2} }{ {y}^{2} } }

so we get

2x \times  \sqrt[3]{2 {y}^{2} \times  \frac{1}{ {y}^{3} }  }

=  \frac{2x}{y}  \times  \sqrt[3]{2 {y}^{2} }

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i will use proportions for this.

 x          52

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2650    100

Cross multiply and u get 1378.

Hope it helps. :)

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3 years ago
(PLEASE HELP)<br> Which value of x makes this equation true<br> -90=-100+x
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Answer:

-0.9

Step-by-step explanation:

-0.9 × 100 = -90

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3 years ago
15 - 3k = 10(k-5) <br> Can someone please answer this
solmaris [256]

Answer:

k = 5

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Order of Operations: BPEMDAS
  • Equality Properties

Step-by-step explanation:

<u>Step 1: Define equation</u>

15 - 3k = 10(k - 5)

<u>Step 2: Solve for </u><em><u>k</u></em>

  1. Distribute 10:                              15 - 3k = 10k - 50
  2. Add 3k to both sides:                15 = 13k - 50
  3. Add 50 to both sides:                65 = 13k
  4. Divide 13 on both sides:            5 = k
  5. Rewrite:                                       k = 5

<u>Step 3: Check</u>

<em>Plug in k into the original equation to verify it's a solution.</em>

  1. Substitute in <em>k</em>:                    15 - 3(5) = 10(5 - 5)
  2. Subtract:                              15 - 3(5) = 10(0)
  3. Multiply:                               15 - 15 = 0
  4. Subtract:                              0 = 0

Here we see that 0 does indeed equal 0.

∴ k = 5 is a solution of the equation.

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3 years ago
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