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Akimi4 [234]
3 years ago
10

7+√5/7-√5 + 7-√5/7+√5 = a + 7/11√5b

Mathematics
1 answer:
BaLLatris [955]3 years ago
6 0

The values of a and b in the given surd expression are; a = 27/22 and b = 1/2

<h3>How to simplify surds?</h3>

The correct expression is;

(7 + √5)/(7 - √5) - (7 - √5)/(7 + √5) = a + (7/11)√5b

Let us first rationalize the denominator of the first term to get;

(7 + √5)/(7 - √5) = [(7 +√5)/(7-√5)] * [(7 + √5)/(7 + √5)]

⇒ (54 + 14√5)/44

⇒ (27/22) + 7(√5)/22

Let us first rationalize the denominator of the second term to get;

[(7 - √5)/(7 + √5)] * [(7 - √5)/(7 - √5)]

⇒ (54 - 14√5)/44

⇒ (27/22) - 7(√5)/22

Thus;

a = 27/22 and b = 1/2

Read more about surds at; brainly.com/question/24700530

#SPJ1

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Assume the random variable X is normally distributed with mean mu equals 50 and standard deviation sigma equals 7. Compute the p
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Answer:

The probability that <em>X</em> is less than 42 is 0.1271.

Step-by-step explanation:

The random variable <em>X </em>follows a Normal distribution.

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SD (X) = <em>σ</em> = 7.

A normal distribution is continuous probability distribution.

The Normal probability distribution with mean µ and standard deviation σ is given by,

f_{X}(\mu, \sigma)=\frac{1}{\sigma\sqrt{2\pi}}e^{-(x-\mu)^{2}/2\sigma^{2}};\ -\infty

To compute the probability of a Normal random variable we first standardize the raw score.

The raw scores are standardized using the formula:

z=\frac{x-\mu}{\sigma}

These standardized scores are known as <em>z</em>-scores and they follow normal distribution with mean 0 and standard deviation 1.

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P(X

*Use a <em>z</em>-table for the probability.

Thus, the probability that <em>X</em> is less than 42 is 0.1271.

The normal curve is shown below.

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