Answer:
x=2
Step-by-step explanation:
We will use the secant-secant Formula:
(whole secant) x (external part) = (whole secant) x (external part)
(1+x+4) * (x+4) = (11+x+1) * (x+1)
Combine like terms
(x+5) (x+4) = (x+12) (x+1)
FOIL
x^2 + 4x+5x + 20 = x^2 + x+ 12x + 12
Combine like terms
x^2 + 9 x + 20 = x^2 + 13 x + 12
Bring everything to the left
x^2 + 9 x + 20- (x^2 + 13 x + 12) = x^2 + 13 x + 12-( x^2 + 13 x + 12)
x^2 + 9 x + 20- (x^2 + 13 x + 12) =0
Distribute the minus sign
x^2 + 9 x + 20- x^2 - 13 x - 12 =0
Combine like terms
-4x +8 = 0
Subtract 8 from each side
-4x+8-8=0-8
-4x=-8
Divide each side by -4
-4x/-4 = -8/-4
x=2
Answer:
ur wegfew
Step-by-step explanation:
Answer:
Step-by-step explanation:
If we expand 4(3+x), we get (4*3)+(4*x).
Then we do 4*3 to get 12 and 4*x to get 4x
(3+3+3+3) is the same thing as 4*3, because we are adding 3 together 4 times. (3+3+3+3) gives us 12 as well, since they are the same thing.
(x+x+x+x) is the same thing because we are adding x together 4 times, which is the same thing as (4*x). (x+x+x+x) gives us 4x as well.
Hope this helps.
Answer:
I think is A
Step-by-step explanation:
-7x -13 ≥ 8
+13 +13
-7x ≥ 21 (then, divide by -7 and when u divide by a negative number, the sign flip)
Answer: x ≤ -3
Step-by-step explanation:
Graph 1 is a parabola and has 2 x points and a turning point
meaning it has a minimum and a maximum point.
conclave points are the highs and lows, once you show this in table then you can interpreted them on a graph see the examples attached.
Graph 1 is opposite to shown interpreted conclave so instead of --c++
we write + + c - - and draw on quadrant 1 instead of quadrant 3
graph 2 is decreasing so instead of -+ c then + + it would show + - c then - - so the curve stays in quadrant 3 and 4. Also where c is we draw a 0 and say whether it is minimum or maximum point.
Both graph 1 and 2 demonstrate minimum points for their f(x) for c.
so in your workings within the table you write min as seen in red within the attachment. They wrote max, but you write min as you are in decreasing conclave fx values that reach min point c then they increase and become parabolas.
