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2 years ago

5

* GEOMETRY please help me show the work for 9, 10, and 11!!

1 answer:

KiRa [710]2 years ago

5 0

9) Diagonals of a parallelogram bisect each other, so KN=NM. Thus, KM=13.5+13.5=27 cm

10) Opposite sides of a parallelogram are congruent, so LM=KJ=17 cm

11) Based on Question 9, MN=13.5 cm

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Find the slope of the line that contains the following points. e(5,7), f(3,1)

Amanda [17]

Look up online "equation calculator" and it should be the first one to appear, "Symbolab" supper easy way to help you with problems!

3 0

3 years ago

Find the arc length of the given curve between the specified points. x = y^4/16 + 1/2y^2 from (9/16), 1) to (9/8, 2).

lutik1710 [3]

Answer:

The arc length is $\dfrac{21}{16}$

Step-by-step explanation:

Given that,

The given curve between the specified points is

$x=\dfrac{y^4}{16}+\dfrac{1}{2y^2}$

The points from $(\dfrac{9}{16},1)$ to $(\dfrac{9}{8},2)$

We need to calculate the value of $\dfrac{dx}{dy}$

Using given equation

$x=\dfrac{y^4}{16}+\dfrac{1}{2y^2}$

On differentiating w.r.to y

$\dfrac{dx}{dy}=\dfrac{d}{dy}(\dfrac{y^2}{16}+\dfrac{1}{2y^2})$

$\dfrac{dx}{dy}=\dfrac{1}{16}\dfrac{d}{dy}(y^4)+\dfrac{1}{2}\dfrac{d}{dy}(y^{-2})$

$\dfrac{dx}{dy}=\dfrac{1}{16}(4y^{3})+\dfrac{1}{2}(-2y^{-3})$

$\dfrac{dx}{dy}=\dfrac{y^3}{4}-y^{-3}$

We need to calculate the arc length

Using formula of arc length

$L=\int_{a}^{b}{\sqrt{1+(\dfrac{dx}{dy})^2}dy}$

Put the value into the formula

$L=\int_{1}^{2}{\sqrt{1+(\dfrac{y^3}{4}-y^{-3})^2}dy}$

$L=\int_{1}^{2}{\sqrt{1+(\dfrac{y^3}{4})^2+(y^{-3})^2-2\times\dfrac{y^3}{4}\times y^{-3}}dy}$

$L=\int_{1}^{2}{\sqrt{1+(\dfrac{y^3}{4})^2+(y^{-3})^2-\dfrac{1}{2}}dy}$

$L=\int_{1}^{2}{\sqrt{(\dfrac{y^3}{4})^2+(y^{-3})^2+\dfrac{1}{2}}dy}$

$L=\int_{1}^{2}{\sqrt{(\dfrac{y^3}{4}+y^{-3})^2}dy}$

$L= \int_{1}^{2}{(\dfrac{y^3}{4}+y^{-3})dy}$

$L=(\dfrac{y^{3+1}}{4\times4}+\dfrac{y^{-3+1}}{-3+1})_{1}^{2}$

$L=(\dfrac{y^4}{16}+\dfrac{y^{-2}}{-2})_{1}^{2}$

Put the limits

$L=(\dfrac{2^4}{16}+\dfrac{2^{-2}}{-2}-\dfrac{1^4}{16}-\dfrac{(1)^{-2}}{-2})$

$L=\dfrac{21}{16}$

Hence, The arc length is $\dfrac{21}{16}$

6 0

2 years ago

Solve for x. Round to the nearest tenth.

kondor19780726 [428]

Answer:

22.8

Step-by-step explanation:

$a^{2} +b^{2} =c^{2} \\20^{2} +11^{2} =x^{2} \\400+121=x^{2}\\\sqrt{521} =x\\\\or\\\\22.8 = x$

5 0

3 years ago

There are 20 alligators in the swamp. Each year, the number of alligators increases by 25%. There are 25 crocodiles in the swamp

Genrish500 [490]

A)

A=20(1.25^t)

C=25+10t

b)

A(4)=20(1.25^4)≈48.82≈49 alligators to nearest whole alligator

C(4)=25+10(4)=65 crocodiles.

c)

20(1.25^t)=25+10t

1.25^t=1.25+0.5t

t≈7

4 0

2 years ago

The probability that an egg on a production line is cracked is 0.01. Two eggs are selected at random from the production line. F

musickatia [10]

Answer:

$P(X \geq 1)=1-P(X$

$P(X=0)=(2C0)(0.01)^0 (1-0.01)^{2-0}=0.9801$

And replacing we got:

$P(X \geq 1) = 1-0.9801 = 0.0199$

Step-by-step explanation:

Let X the random variable of interest "number of craked eggs", on this case we now that:

$X \sim Binom(n=2, p=0.01)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

And we want to find this probability:

$P(x \geq 1)=1-P(X$

And we can find the probability:

$P(X=0)=(2C0)(0.01)^0 (1-0.01)^{2-0}=0.9801$

And replacing we got:

$P(X \geq 1) = 1-0.9801 = 0.0199$

5 0

2 years ago