He sold 76 shirts and 24 pants.
Step-by-step explanation:
Given,
Cost of one t-shirt = $20
Cost of one pants = $45
Total items sold = 100
Total sales = 2600
Let,
x be the number of t-shirts
y be the number of pants
According to given statement;
x+y=100 Eqn 1
20x+45y=2600 Eqn 2
Multiplying Eqn 1 by 20
Subtracting Eqn 3 from Eqn 2
Dividing both sides by 25
Putting in Eqn 1
He sold 76 shirts and 24 pants.
Keywords: linear equations, subtraction
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Answer:
The price of each CD before tax is $15.70
Step-by-step explanation:
Given that:
Number of CDs bought by Reuben = 5
Cost of five CDs = $81.50
Sales tax on each CD = $0.60
Sales tax on 5 CDs = 0.60*5 = $3.00
Price of CDs without tax = 81.50 - 3.00 = $78.50
Price of each CD =
Price of each CD =
Price of each CD = $15.70
Hence,
The price of each CD before sales tax is $15.70
D. 80
If you expand the entirety of the polynomial, you get the following:
32x^5+80x^4y+80x^3y^2+40x^2y^3+10xy^4+y^5
Answer: 4:20 but that simplified would be 1:5
Triangles to squares
9514 1404 393
Answer:
250
Step-by-step explanation:
Let 'a' represent the number of adult tickets.
a +(a -73) = 427
2a = 500 . . . . . add 73
a = 250 . . . . . . divide by 2
250 adult tickets were sold.
_____
<em>Additional comment</em>
I call this a "sum and difference problem" because we are given the total of two values and the difference between them. As you can see here, the larger of the two values is the average of the given numbers, their sum divided by 2. This is the generic solution to such a problem: the larger number is the average of the given sum and difference.