Step One
Develop a formula for the perimeter.
Argument
What you see is a semicircle going upwards and another one going downwards. Two semicircles =1 circle.
The "perimeter" [Circumfrence] of a whole circle = 2*pi*r
We are told that whatever you call this the perimeter is 8pi + 16
Step Two
Set up the equation
8pi + 16 = 2*pi*r + 4r Including the line connecting these two.
Step Three
Take out the common factors on the left and right.
8(pi + 2) = 2r(pi + 2) Divide both sides by pi + 2
8 = 2r Divide by 2
4 = r
Sorry. I didn't know the meaning of perimeter. Mathmate is perfectly correct.
Answer:
ok
Step-by-step explanation:
the answer is and answer
We will start off working on the right hand side.
<span>cot x - tan x </span>
<span>= [cos x / sin x] - [sin x / cos x] </span>
<span>= [(cos x)^ 2 - (sin x)^2] / [sin x cos x] </span>
<span>This is where it gets a bit tougher if you do not have your formula list with you. </span>
<span>(cos x)^ 2 - (sin x)^2 = cos(2x) </span>
<span>sin 2x = 2 sin x cos x </span>
<span>Note that by arranging the second formula, we will have sin x cos x = (1/2) sin 2x </span>
<span>Hence, we will get: </span>
<span>[(cos x)^ 2 - (sin x)^2] / [sin x cos x] </span>
<span>= [cos 2x] / (1/2)[sin 2x] </span>
<span>= 2[cos 2x] / [sin 2x] </span>
<span>= 2cot 2x </span>
Answer:
hunter green
Step-by-step explanation:
what about you ??
have a super day
-tay
We have that
<span>p(t)=-3t^2+18t-4
using a graphing tool, we can see the maximum of the graph
(see the attached figure)
A) </span><span>In what year of operation does Mr. Cash’s business show maximum profit?
</span>
Mr. Cash’s business show maximum profit at year 3 (maximum in the parabole)
<span>B) What is the maximum profit?
23 (hundred of thousand of dollars) = 2.300.000 dollars
</span>c) What time will it be two late?
(This is the time when the graph crosses zero and the profits turn into losses )
5.77 years, or an estimate of about 69 months.