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Keith_Richards [23]
1 year ago
11

What is the base of a triangle with an area of 207 square inches and a height of 18 inches

Mathematics
1 answer:
White raven [17]1 year ago
4 0
Answer: 23 in

Step-by-Step Explanation:

Height (h) = 18 in
Base (b) = ?
Area (A) = 207 sq. in

We know,
Area of a Triangle = 1/2 * b * h

Therefore,
1/2 * b * h = 207
1/2 * b * 18 = 207
b * 9 = 207
9b = 207
b = 207/9
=> b = 23

Base (b) = 23 in
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Can anyone help me!​
zhenek [66]

Answer:

\large \text{$ \sf 2^{-64}$}

Step-by-step explanation:

Given:

\large \text{$ \sf (256)^{-4^{\frac{3}{2}}}$}

This reads as:  256 to the power of "-4 to the power of 3/2".

Therefore, we need to deal with the "-4 to the power of 3/2" first.

Rewrite the 4 as 2²:

\large \text{$ \sf \implies -(2^2)^{\frac{3}{2}}$}

\textsf{Apply exponent rule} \quad (a^b)^c=a^{bc}:

\large \text{$ \sf \implies -2^{\left(2 \times \frac{3}{2}\right)}$}

\large \text{$ \sf \implies -2^{3}$}

Therefore:

\large \text{$ \sf \implies -2^3=(-2)(-2)(-2) = -8$}

Replace "-4 to the power of 3/2" with -8 :

\large \text{$ \sf \implies 256^{-8}$}

Rewrite 256 as 2⁸ :

\large \text{$ \sf \implies (2^8)^{-8}$}

\textsf{Again, apply exponent rule} \quad (a^b)^c=a^{bc}:

\large \text{$ \sf \implies 2^{(8 \times -8)}$}

\large \text{$ \sf \implies 2^{-64}$}

In one complete calculation:

\large\begin{aligned} \sf (256)^{-4^{\frac{3}{2}}} & = \sf (256)^{-(2^2)^{\frac{3}{2}}}\\& = \sf (256)^{-2^{\left(2 \times \frac{3}{2}\right)}}\\& =\sf  (256)^{-2^{3}}\\& = \sf (256)^{-8}\\& \sf = (2^8)^{-8}\\& = \sf 2^{(8 \times -8)}\\& =\sf  2^{-64}\end{aligned}

Learn more about exponent rules here:

brainly.com/question/28211147

brainly.com/question/27959936

4 0
1 year ago
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Find the slope of the line passing through the points (-5, 3) and (7, 9) ​
rodikova [14]

\sf{\red{Answer}}

\sf{m =  \frac{1}{2} }

\sf{\purple{Explanation}}

\sf{m =  \frac{y_{2}- y_{1}}{m_{2} - m_{1}} }

\sf{m =  \frac{9- 3}{7- ( - 5)} }

\sf{m =  \frac{6}{7 +  5} }

\sf{m =  \frac{6}{12} }

\sf{m =  \frac{1}{2} }

3 0
1 year ago
I need help on this plz
balandron [24]

Answer:

(2) angle1 = 139, angle2 = 41, angle4 = 41, angle5 = 139, angle6 = 41, angle7 = 139, angle8 = 41

(3) angle1 = 150, angle2 = 30, angle4 = 30, angle5 = 150, angle6 = 30, angle7 = 150, angle8 = 30

Step-by-step explanation:

All angle are either equal to each other or supplementary.  I use corresponding angles and vertical angles to prove each of the above.

For number 3, angle 3 and angle 8 are supplementary, so they add up to 180:

8x +70 + (4x - 10) = 180

12x + 60 = 180

12x = 120

x = 10

So if x = 10, then 8x + 70 = 8(10) + 70 = 150

That means all angles are either 150 or 30 for number 3.

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3 years ago
Find the equation of the line.
Soloha48 [4]

Answer:

-2/9

Step-by-step explanation:

5 0
3 years ago
Help me with my math **50 pts** I mark brainliest**
s2008m [1.1K]

Answer:

2)

2x + 6x + 8 = 32

collect like terms

8x + 8 = 32

move the constant to the right hand side and change its sign.

8x = 32 - 8

Subtract the numbers

8x = 24

Divide both sides of the equation by 8

x = 3

8 0
3 years ago
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