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dexar [7]
1 year ago
13

Determine the value of Y.

Mathematics
2 answers:
aleksandr82 [10.1K]1 year ago
7 0

Answer:

y=10°

Step-by-step explanation:

Here,

→(3x+18)°=(5x-4)°

→18°+4°=5x-3x

→22°=2x

→x=11°

Also,

3(4y+3)°+5x-4°=180°[The sum of the linear pair is 180°]

12y+9°+5x-4°=180°

12y+5°+5×11°=180°

12y+5°+55°=180°

12y=180°-60°

12y=120°

y=120°/12

y=10°

kolbaska11 [484]1 year ago
4 0

Opposite angles are equal

  • 3x+18=5x-4
  • 22=2x
  • x=11

Now

linear pairs are supplementary

  • 3x+18+3(4y+3)=180
  • 3(11)+18+12y+9=180
  • 33+18+12y+9=180
  • 12y+60=180
  • 12y=120
  • y=10
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Step-by-step explanation:

We are given the following dimensions of the triangular pyramid:

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Height of triangular base = 5.2mm

Base of lateral face (triangular) = 6mm

Height of lateral face (triangular) = 8mm

a) To find Area of base of pyramid:

We know that it is a triangular pyramid and the base is a equilateral triangle. \text{Area of triangle = } \dfrac{1}{2} \times \text{Base} \times \text{Height} ..... (1)\\

{\Rightarrow \text{Area of pyramid's base = }\dfrac{1}{2} \times 6 \times 5.2\\\Rightarrow 15.6\ mm^{2}

b) To find area of one lateral surface:

Base = 6mm

Height = 8mm

Using equation (1) to find the area:

\Rightarrow \dfrac{1}{2} \times 8 \times 6\\\Rightarrow 24\ mm^{2}

c) To find the lateral surface area:

We know that there are 3 lateral surfaces with equal height and equal base.

Hence, their areas will also be same. So,

\text{Lateral Surface Area = }3 \times \text{ Area of one lateral surface}\\\Rightarrow 3 \times 24 = 72 mm^{2}

d) To find total surface area:

Total Surface area of the given triangular pyramid will be equal to <em>Lateral Surface Area + Area of base</em>

\Rightarrow 72 + 15.6 \\\Rightarrow 87.6\  mm^{2}

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a) Area of the base of the pyramid = 15.6\ mm^{2}

b) Area of one lateral face = 24\ mm^{2}

c) Lateral Surface Area = 72\ mm^{2}

d) Total Surface Area = 87.6\ mm^{2}

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2 years ago
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