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valina [46]
2 years ago
8

How do you calculate the rate of a reaction?

Chemistry
2 answers:
NeTakaya2 years ago
6 0
Rate of reaction

The rate of a reaction is a measure of how quickly a reactant is used up, or a product is formed.

There are different ways to determine the rate of a reaction. The method chosen usually depends on the reactants and products involved, and how easy it is to measure changes in them.

The mean rate of reaction can be calculated using either of these two equations:


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Measuring mass

The change in mass of a reactant or product can be followed during a reaction. This method is useful when carbon dioxide is a product which leaves the reaction container. It is not suitable for hydrogen and other gases with a small relative formula mass, Mr.

The units for rate are usually g/s or g/min.
ss7ja [257]2 years ago
6 0
Rate of reaction . The mean rate of reaction can be calculated using 2 equations.
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dimulka [17.4K]
<span>The first ionization energy is the energy that is obligatory in order to eliminate the first electron from an atom(neutral) in the GAS phase
, the second ionization energy is defined as  the energy required to remove the second electron from an atom(+1 ion) in the GAS phase.
</span>the third ionization energy is the energy it takes to remove an electron from a 2+ ion. (That means that the atom has already lost two electrons, you are now removing the third.) 
<span> Ionization energy will normally increase for every electron that is removed and increases from left to right in the periodic table and moving up the periods
hope it helps</span>
4 0
4 years ago
On a cool, rainy day, the barometric pressure is 746 mmHg. Calculate the barometric pressure in centimeters of water (cmH2O) (d
docker41 [41]

Answer:

100.71 cm H2O

Explanation:

In a fluid column barometer, the height of the fluid column is proportional to the pressure. The pressure is by definition:

P=\frac{F}{A}, where F is a force and A is the area.

In a column barometer the force is given by the weight of the fluid:

F=m*g, and the mass may be expressed as m=p*V, where p is the density and V is the volume.

Replacing this in the pressure definition:

P=\frac{pVg}{A}

In a constant cross section area column, the volume may be calculated as:

V=A*h where A is the area and h the height. Replacing this in the previous equation:

P=\frac{pAhg}{A}=pgh

Different columns may be over the same pressure, so:

P_{w}=P_{Hg}\\ p_{w}h_{w}g=p_{Hg}h_{Hg}g\\

Dividing each part for gravity constant:

p_{w}h_{w}=p_{Hg}h_{Hg}

And isolating hw:

h_{w}=\frac{p_{Hg}h_{Hg}}{p_{w} } \\h_{w}=\frac{13.5*746}{1.00}=10071 mm

It is equal to 1007,1 cm.

7 0
3 years ago
Someone please help! this is the last question<br>I only need help with B.<br><br>​
ludmilkaskok [199]

1. mol ratio of Al(NO₃)₃ : Na₂CO₃ = 2 : 3

2. Na₂CO₃ as a limiting reactant

<h3>Further explanation</h3>

Given

Reaction

2 Al(NO₃)₃ + 3 Na₂CO₃ → Al₂(CO₃)₃ + 6 NaNO₃

Required

mol ratio

Limiting reactant

Solution

The reaction coefficient in the chemical equation shows the mole ratio of the components of the compound involved in the reaction (reactants and products)

1. From the equation mol ratio of Al(NO₃)₃ : Na₂CO₃ = 2 : 3

2. mol : coefficient of Al(NO₃)₃ : Na₂CO₃ = 2 mole/2 : 2 mole/3 = 1 : 0.67

Na₂CO₃ as a limiting reactant (smaller)

6 0
3 years ago
What should be the mole fraction of O2 in the gas mixture the diver breathes in order to have the same partial pressure of oxyge
Nutka1998 [239]

The question is incomplete, here is the complete question:

A scuba diver is at a depth of 355 m, where the pressure is 36.5 atm.

What should be the mole fraction of O_2 in the gas mixture the diver breathes in order to have the same partial pressure of oxygen in his lungs as he would at sea level? Note that the mole fraction of oxygen at sea level is 0.209.

<u>Answer:</u> The mole fraction of oxygen in the gas mixture is 0.00573

<u>Explanation:</u>

To calculate the partial pressure, we use the equation given by Raoult's law, which is:

p_{A}=p_T\times \chi_{A}      ........(1)

where,

p_A = partial pressure of oxygen at sea level = ?

p_T = total pressure at sea level = 1.00 atm

\chi_A = mole fraction of oxygen at sea level = 0.209

Putting values in equation 1, we get:

p_{O_2}=1.00atm\times 0.209\\\\p_{O_2}=0.209atm

As, partial pressure of the oxygen in the diver's lungs is equal to the partial pressure of oxygen at sea level

We are given:

p_T=36.5atm\\p_{O_2}=0.209atm

Putting values in equation 1, we get:

0.209atm=36.5atm\times \chi_{O_2}\\\\\chi_{O_2}=\frac{0.209}{36.5}=0.00573

Hence, the mole fraction of oxygen in the gas mixture is 0.00573

3 0
3 years ago
This balanced chemical equation represents a chemical reaction: 6no + 4nh3 → 5n2 + 6h2o what volume of nh3 gas, at standard temp
Liula [17]

The answer is: volume of ammonia gas is 7.4 L.

Chemical reaction: 6NO + 4NH₃ → 5N₂ + 6H₂O.

m(NO) = 15 g; mass of nitrogen(II) oxide.

M(NO) = 30 g/mol; molar mass of nitrogen(II) oxide.

V(NH₃) = ?

n(NO) = 15 g ÷ 30 g/mol.

n(NO) = 0.5 mol; amount of nitrogen(II) oxide.

From chemical reaction: n(NO) : n(NH₃) = 6 : 4.

0.5 mol : n(NH₃) = 6 : 4.

n(NH₃) = 0.33 mol; amount of ammonia.

Vm = 22.4 L/mol; molar volume at STP.

V(NH₃) = 0.33 mol · 22.4 L/mol..

V(NH₃) = 7.4 L.

3 0
4 years ago
Read 2 more answers
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