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saul85 [17]
3 years ago
6

In the process of ionization, what is the relationship between the second ionization energy (I2) and the third ionization energy

(I3)?
Chemistry
1 answer:
dimulka [17.4K]3 years ago
4 0
<span>The first ionization energy is the energy that is obligatory in order to eliminate the first electron from an atom(neutral) in the GAS phase
, the second ionization energy is defined as  the energy required to remove the second electron from an atom(+1 ion) in the GAS phase.
</span>the third ionization energy is the energy it takes to remove an electron from a 2+ ion. (That means that the atom has already lost two electrons, you are now removing the third.) 
<span> Ionization energy will normally increase for every electron that is removed and increases from left to right in the periodic table and moving up the periods
hope it helps</span>
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First We need to understand the structure of trimethylamine

Due to the grades of the bond in the nitrogen with a hybridization sp3 is 108° approximately, then is generated a dipole magnetic at the upper side of the nitrogen, this dipole magnetic going to attract a hydrogen molecule of the water making the water more alkaline

C3H9N+ H2O --> C3H9NH + OH-

k=\frac{[C3H9NH]*[OH-]}{[C3H9N]}

Then:

The concentration of the trimethylamine is 0.3 and the concentration of the ion C3H9NH is equal to the OH- relying on the stoichiometric equation. We could find the concentration of the OH- ion with the square root of the multiplication between k and the concentration of trimethylamine

[OH-]=\sqrt{ 0.3*7.42x10^{-4}}

[OH-]=0.01

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pH=12

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