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tia_tia [17]
2 years ago
11

Find the area of the shaded region

Mathematics
1 answer:
Simora [160]2 years ago
3 0
Answer: D. The area is 50 square meters if the shaded area looks like .

Explanation:
assuming this is a rectangle, the larger region area is 15*5= 75 square meters.
The smaller region’s area would be 10*5= 50 square meters.
• remember that A=lw, where l is length and w is width.


Without an illustration & on the assumption this is a rectangular region, here are the conclusions:
• given these two areas,
If the shaded area looks like , the area is just 50 square meters because the dimensions needed to solve for the area were given.
OR
• If the shaded region looks like subtract the smaller area from the larger one: 75-50= 25 square meters. (However, given that this is not an answer choice, I don’t think the illustration would look like this).
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Jason is pulling a box across the room. He is pulling with a force of 19 newtons and his arm is making a 30 angle with the horiz
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We are to solve for the vertical and horizontal component of the force he is pulling with.

1. The vertical component of Jason's force is 9.5Newtons.

2.The horizontal component of Jason's force is 2.67Newtons.

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4.Therefore, Resultant, R is 72.11

Question 1:

If Jason is pulling with a force of 19 Newtons and his arm is at an angle of 30° with the horizontal.

By resolving Jason's force of pull in the vertical direction, Fy = 19 × Sin 30° = 9.5 Newtons.

The <em>vertical</em> component of Jason's force is 9.5 Newtons.

Question 2:

Also,If Jason is pulling with a force of 14 Newtons and his arm is at an angle of 79° with the <em>horizontal</em>.

By resolving Jason's force of pull in the <em>horizontal</em> direction, Fx = 14 × Cos79° = 2.67 Newtons.

The horizontal component of Jason's force is 2.67Newtons.

Question 3:

If Jason is pulling with a force of 23Newtons and his arm is at an angle of 30° with the <em>horizontal</em>.

By resolving Jason's force of pull in the <em>vertical</em> direction, Fy = 23 × Sin 30° = 11.5Newtons.

The vertical component of Jason's force of pull is, 11.5Newtons.

If the box weighs 24Newtons.

By treating up as the +ve vertical direction and down as the -ve vertical direction,

Therefore, the weight of the box acts in the -ve vertical direction, while Jason's vertical force component acts in the +ve vertical direction.

Therefore, the net force in the vertical direction is = 11.5Newtons + (-24Newtons)

Therefore, the net force in the vertical direction is -12.5Newtons.

Question 4:

If there are two forces at right angles to eachother, one of magnitude, 68 and the other of magnitude, 24.

The resultant force on the object can be obtained by Pythagoras theorem (Triangle law of forces).

Resultant, R = √(68²+24²) = √5200.

Therefore, Resultant, R = 72.11

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