Answer:
It is a function.
Step-by-step explanation:
You can test if a graph is a function if you draw a vertical line anywhere on the graph and you see it hits two points.
This is the table for the graph.
![\left[\begin{array}{ccc}x&y\\-3&0\\0&1\\3&2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx%26y%5C%5C-3%260%5C%5C0%261%5C%5C3%262%5Cend%7Barray%7D%5Cright%5D)
Remember these rules:
- Each x value, or input, has its unique y value, or output
- If you draw a vertical line anywhere on the graph, it should only go through one point
We can check these two rules for this graph:
- Does each x value have its own, unique y value? Yes
- If you draw a vertical line anywhere on the graph, does it only go through one point? Yes, there are no overlaps
Keep in mind that two different x-values can have the same y value.
Figure 1:
It has two x values with the same y-values.
Figure 2 and 3:
The vertical line goes through two points. So the same x-value has two different y-values.
-Chetan K
Answer:
10X + 20 +5X +25 = 180
15x=180-45
X= 135/15
X=9
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The area of a right angled triangle with sides of length 9cm, 12cm and 15cm in square centimeters is 54 sq cm.
The formula to calculate the area of a right triangle is given by:
Area of Right Triangle, A = (½) × b × h square units
Where, “b” is the base (adjacent side) and “h” is the height (perpendicular side). Hence, the area of the right triangle is the product of base and height and then divide the product by 2.
We know that the hypotenuse is the longest side. So, the area of a right angled triangle will be half of the product of the remaining two sides.
Given sides of the triangle:
a=9cm
b=12cm
c=15cm
From this we know that the hypotenuse is c. Are of the triangle will be obtained by the other two sides.
∴Area = 
x 9 x 12
= 54
Let:
Vbu= Volume of the buret
Vbk= Volume of the beaker
A buret initially contains 70.00 millimeters of a solution and a beaker initially contains 20.00 ml of the solution the buret drips solution into the Beaker. each drip contains 0.05 mL of solution, therefore:
x = Number of drips
a = volume of each drip
after how many drips will the volume of the solution in the buret and beaker be equal ? Vbu = Vbk:
