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Tatiana [17]
2 years ago
8

The Range of this graph

Mathematics
1 answer:
Tomtit [17]2 years ago
6 0

Answer:

the maximum range is 2 the minimum range is -9

Step-by-step explanation:

im not great at explaining things

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1. What is the value of x? Show all of your work.
asambeis [7]
AB^2 + BC^2 = AC^2
AB^2 + 6^2 = square root 117^2
AB^2 + 36 = 117

Now subtract 117 from both sides
AB^2 = 81
AB = square root 81 = 9
\sqrt{81}  = 9
Therefore AB is 9 cms.
3 0
3 years ago
The mean consumption of water per household in a city was 1425 cubic feet per month. Due to a water shortage because of a drough
liberstina [14]

Answer:

a)t=\frac{1175-1425}{\frac{250}{\sqrt{100}}}=-10    

The degrees of freedom are given by:

df=n-1=100-1=99  

The p value for this case would be given by:

p_v =P(t_{99}  

Since the p value is significantly lower than he significance level given we have enough evidence to reject the null hypothesis and we can conclude that the true mean is lower than 1425

b) For this case we need to find a critical value in the t distribution with  99 degrees of freedom who accumulates 0.025 of the area in the right tail and we got:

t_{\alpha/2}=1.984

Since the calculated value is higher than the critical value we can reject the null hypothesis at the significance level provided and we can say that the true mean is higher than 1425

Step-by-step explanation:

Information given

\bar X=1175 represent the sample mean for the cubic feets of households

\sigma=250 represent the population standard deviation

n=100 sample size  

\mu_o =1425 represent the value to verify

\alpha=0.025 represent the significance level

t would represent the statistic

p_v represent the p value

Part a

We want to test that the mean consumption of water per household has decreased due to the campaign by the city council, the system of hypothesis would be:  

Null hypothesis:\mu \geq 1425  

Alternative hypothesis:\mu < 1425  

Since we don't know the deviation the statistic is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

The statistic is given by:

t=\frac{1175-1425}{\frac{250}{\sqrt{100}}}=-10    

The degrees of freedom are given by:

df=n-1=100-1=99  

The p value for this case would be given by:

p_v =P(t_{99}  

Since the p value is significantly lower than he significance level given we have enough evidence to reject the null hypothesis and we can conclude that the true mean is lower than 1425

Part b

For this case we need to find a critical value in the t distribution with  99 degrees of freedom who accumulates 0.025 of the area in the right tail and we got:

t_{\alpha/2}=1.984

Since the calculated value is higher than the critical value we can reject the null hypothesis at the significance level provided and we can say that the true mean is higher than 1425

6 0
3 years ago
Which number is a prime number??<br><br> 111<br> 121<br> 131<br> 141
Fynjy0 [20]
The prime number you are looking for is 141
5 0
2 years ago
Steve paid 10% tax on a purchase of 40$
aivan3 [116]
He would need to pay $44 for the purchase because
10% x $40 = $4
$40 + $4 = $44

hope this helped ((:
5 0
3 years ago
Can yall pls help me
Leviafan [203]
A. Learning and religion
6 0
2 years ago
Read 2 more answers
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