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Brums [2.3K]
3 years ago
11

Solve the following problems using 5-D process part 2

Mathematics
1 answer:
svet-max [94.6K]3 years ago
5 0

The two problems are almost identical: you have to set up a system, and then solve it.

In the first case, let g and b be, respectively, the number of girls and boys.

We know that g=2b+4 (the number of girls in the Spanish Club is four more than twice the number of boys). Also, we know that g+b=61 (there are 61 students in total).

So, we have the system

\begin{cases}g=2b+4\\g+b=61\end{cases}

We can use the first equation to substitute in the second

g+b=61 \iff (2b+4)+b=61 \iff 3b+4=61 \iff 3b=57 \iff b=19

And then solve for g:

g=2b+4=2\cdot 19+4=38+4=42

For the second problem, let c and j be the number of pins knocked down by, respectively, Carrie and John. Just like before, we have the system

\begin{cases}c=j+12\\c+j=230\end{cases}

And you can solve it in the very same way we solved the previous one.

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3 of 1/10 of what number
vampirchik [111]

Answer:

3/10

Step-by-step explanation: you multiply 3 and 1/10

8 0
4 years ago
Read 2 more answers
1.Measurement of segment QR is 2Measurement of segment TS is 3.Measurement if segment QT is
Whitepunk [10]

We need x and y

Opposite sides of a parallelogram are equal

  • QR=TS
  • 5x-1=2x+5
  • 3x=6
  • x=2

And

  • RS=QT
  • 3y-2=y+8
  • 2y=10
  • y=5

Hence

  • QR=TS=5x-1=5(2)-1=9
  • RS=QT=y+8=5+8=13

#3

Segment QT is 4

so

  • y+8=4
  • y=4+8
  • y=12

Another way

  • x is 5

  • old x is 2

So

scale factor:-

  • k=5/2=2.5

Find y

  • y=5k
  • y=5(2.5)
  • y=12.5
5 0
2 years ago
Read 2 more answers
Which of the following graphs is f(2) = 5
ser-zykov [4K]

Answer:

None.

Step-by-step explanation:

Where are the graphs? We need the extra information to complete this problem.

5 0
3 years ago
The factors of a quadratic function are 2x-3 and x-3. what is the axis of symmetry of this function?
Crank
F : R -> R, f(x) = ( 2x - 3)( x - 3 ) => f(x) = 2x^2 - 9x + 9;
The axis of symmetry is x = - b / (2a) => x = 9 / 4.
3 0
3 years ago
Por favor responder a esta pregunta
ahrayia [7]
Por determinante:
5...1...1
1...0...1 = 0 --> se o determinante for igual a 0, os pontos estarão alinhados.
3...3...1

calculando: (5 x 0 x 1 + 1 x 1 x 3 + 1 x 3 x 1) - (1 x 0 x 3 + 1 x 1 x 1 + 3 x 1 x 5) = 
0 + 3 + 3 - 0 - 1 - 15 = 
6 - 1 - 15 = 
5 - 15 = - 10 --> como não deu zero, os pontos não estão alinhados.
4 0
3 years ago
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