Yes it is true that commercial truck owners violate laws requiring front license plates at a higher rate than owners of passenger cars because null hypothesis is rejected.
Given among 2049 Connecticut passenger cars, 239 had only rear license plates. Among 334 Connecticut trucks, 45 had only rear license plates.
let
be the probability that commercial cars have rear license plates and
be the probability that connected trucks have rear license plates.
Cars Trucks Total
Total 2049 334 2383
x 239 45 284
p 0.1166 0.1347 0.1191
α=0.05
Hypothesis will be :
![H_{0}:p_{1} =p_{2}](https://tex.z-dn.net/?f=H_%7B0%7D%3Ap_%7B1%7D%20%3Dp_%7B2%7D)
![H_{1} :p_{1} < p_{2}](https://tex.z-dn.net/?f=H_%7B1%7D%20%3Ap_%7B1%7D%20%3C%20p_%7B2%7D)
It is a left tailed test at 0.05 significance.
Standard errors of p=![\sqrt{p(1-p)/n}](https://tex.z-dn.net/?f=%5Csqrt%7Bp%281-p%29%2Fn%7D)
=![\sqrt{(0.1191*0.8809)/2383}](https://tex.z-dn.net/?f=%5Csqrt%7B%280.1191%2A0.8809%29%2F2383%7D)
=
=0.0066
Test statistic Z=p difference/standard error
=(0.1166-0.1347)/0.0066
=-0.0181/0.0061
=-2.967
p value=0.001505<5%
Since p is less than 5% we reject null hypothesis.
We cannot calculate standard deviation so we cannot calculate confidence interval.
Hence there is statistical evidence at 5% significance level to support that commercial truck owners violate laws requiring front license plates at a higher rate than owners of passenger cars.
Learn more about z test at brainly.com/question/14453510
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He should be able to travel 322 miles. It would cost him $33.235 rounded up to $33.24.
Using the Sine rule,
![\frac{\sin A}{A}=\frac{\sin B}{B}=\frac{\sin C}{C}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csin%20A%7D%7BA%7D%3D%5Cfrac%7B%5Csin%20B%7D%7BB%7D%3D%5Cfrac%7B%5Csin%20C%7D%7BC%7D)
![\begin{gathered} \text{Let A = 14m,} \\ Substituting the variables into the formula,Where the length of the wires are, AP = xm and BP = ym[tex]\begin{gathered} \frac{\sin80^0}{14}=\frac{\sin40^0}{x} \\ \text{Crossmultiply,} \\ x\times\sin 80^0=14\times\sin 40^0 \\ Divide\text{ both sides by }\sin 80^0 \\ x=\frac{14\sin40^0}{\sin80^0} \\ x=9.14m \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Ctext%7BLet%20A%20%3D%2014m%2C%7D%20%5C%5C%20Substituting%20the%20variables%20into%20the%20formula%2C%3Cp%3EWhere%20the%20length%20of%20the%20wires%20are%2C%20AP%20%3D%20xm%20and%20BP%20%3D%20ym%3C%2Fp%3E%5Btex%5D%5Cbegin%7Bgathered%7D%20%5Cfrac%7B%5Csin80%5E0%7D%7B14%7D%3D%5Cfrac%7B%5Csin40%5E0%7D%7Bx%7D%20%5C%5C%20%5Ctext%7BCrossmultiply%2C%7D%20%5C%5C%20x%5Ctimes%5Csin%2080%5E0%3D14%5Ctimes%5Csin%2040%5E0%20%5C%5C%20Divide%5Ctext%7B%20both%20sides%20by%20%7D%5Csin%2080%5E0%20%5C%5C%20x%3D%5Cfrac%7B14%5Csin40%5E0%7D%7B%5Csin80%5E0%7D%20%5C%5C%20x%3D9.14m%20%5Cend%7Bgathered%7D)
Hence, the length of wire AP (x) is 9.14m.
For wire BP (y)m,
Sum of angles in a triangle is 180 degrees,
![A^0+P^0+B^0=180^0](https://tex.z-dn.net/?f=A%5E0%2BP%5E0%2BB%5E0%3D180%5E0)
![\begin{gathered} \text{Where A}^0=\text{ unknown,} \\ P^0=80^0\text{ and,} \\ B^0=40^0 \\ A^0+80^0+40^0=180^0 \\ A^0+120^0=180^0 \\ A^0=180^0-120^0 \\ A^0=60^0 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Ctext%7BWhere%20A%7D%5E0%3D%5Ctext%7B%20unknown%2C%7D%20%5C%5C%20P%5E0%3D80%5E0%5Ctext%7B%20and%2C%7D%20%5C%5C%20B%5E0%3D40%5E0%20%5C%5C%20A%5E0%2B80%5E0%2B40%5E0%3D180%5E0%20%5C%5C%20A%5E0%2B120%5E0%3D180%5E0%20%5C%5C%20A%5E0%3D180%5E0-120%5E0%20%5C%5C%20A%5E0%3D60%5E0%20%5Cend%7Bgathered%7D)
Using the side rule to find the length of wire BP,
![\begin{gathered} \frac{\sin 60^0}{y}=\frac{\sin 80^0}{14} \\ \text{Crossmultiply,} \\ y\times\sin 80^0=14\times\sin 60^0 \\ \text{Didive both sides by }\sin 80^0 \\ y=\frac{14\times\sin 60^0}{\sin 80^0} \\ y=12.31m \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Cfrac%7B%5Csin%2060%5E0%7D%7By%7D%3D%5Cfrac%7B%5Csin%2080%5E0%7D%7B14%7D%20%5C%5C%20%5Ctext%7BCrossmultiply%2C%7D%20%5C%5C%20y%5Ctimes%5Csin%2080%5E0%3D14%5Ctimes%5Csin%2060%5E0%20%5C%5C%20%5Ctext%7BDidive%20both%20sides%20by%20%7D%5Csin%2080%5E0%20%5C%5C%20y%3D%5Cfrac%7B14%5Ctimes%5Csin%2060%5E0%7D%7B%5Csin%2080%5E0%7D%20%5C%5C%20y%3D12.31m%20%5Cend%7Bgathered%7D)
Hence, the length of wire BP (y) is 12.31m
Therefore, the length of the wires are (9.14m and 12.31m).
6 cakes ... £2.40
10 cakes ... £x = ?
If you would like to know how much do 10 cakes cost, you can calculate this using the following steps:
6 * x = 10 * 2.40
6 * x = 24 /6
x = 24/6
x = £4
Result: 10 cakes cost £4.