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Kobotan [32]
2 years ago
7

An observer (O) is located 900 feet from a building (B). The observer notices a helicopter (H) flying at a 49° angle of elevatio

n from his line of sight.
How high is the helicopter flying over the building? You must show all work and calculations to receive full credit.
H
49°
900 feet
Mathematics
1 answer:
Natasha2012 [34]2 years ago
6 0

Answer:

<u>1035.33 feet</u>

Step-by-step explanation:

Given :

⇒ Distance between the observer and building = <u>900 feet</u>

⇒ Angle of elevation = <u>49°</u>

<u />

============================================================

Solving :

⇒ tan 49° = h / 900

⇒ h = 900 × 1.1503684072

⇒ h = <u>1035.33 feet</u>

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How many feet long is the shadow of a 15-foot flagpole if a 5-foot woman standing at the base of the flagpole has a shadow that
Vikentia [17]

The height of flagpole is 12.5 feet.

Step-by-step explanation:

Given,

Height of woman = 5 foot

Shadow of woman = 6 feet

Ratio of height to shadow = 5:6

Shadow of flagpole = 15 foot

Height of flagpole = x

Ratio of height to shadow = x:15

Using proportion;

Ratio of height to shadow :: Ratio of height to shadow

5:6::x:15\\

Product of mean = Product of extreme

6*x=15*5\\6x=75

Dividing both sides by 6

\frac{6x}{6}=\frac{75}{6}\\x=12.5

The height of flagpole is 12.5 feet.

Keywords: ratio, proportion

Learn more about proportion at:

  • brainly.com/question/9527422
  • brainly.com/question/9381523

#LearnwithBrainly

8 0
3 years ago
What is the mean deviation of 4, 3, 4, 5, 6, 6, 8, 4?
MrRa [10]
Calculate mean:
4+3+4+5+6+6+8+4=40
40/8=5

Calculate MAD:
1+2+1+0+1+1+3+1=10
10/8= 1.25

Final answer: 1.25
5 0
4 years ago
Read 2 more answers
For which eguation is g = 5 not the solution i need a answer
S_A_V [24]

Answer:

g=5

Step-by-step explanation:

wdym we dont know what equation g=5 is

5 0
3 years ago
If 8 identical blackboards are to be divided among 4 schools,how many divisions are possible? How many, if each school mustrecei
MAXImum [283]

Answer:

There are 165 ways to distribute the blackboards between the schools. If at least 1 blackboard goes to each school, then we only have 35 ways.

Step-by-step explanation:

Essentially, this is a problem of balls and sticks. The 8 identical blackboards can be represented as 8 balls, and you assign them to each school by using 3 sticks. Basically each school receives an amount of blackboards equivalent to the amount of balls between 2 sticks: The first school gets all the balls before the first stick, the second school gets all the balls between stick 1 and stick 2, the third school gets the balls between sticks 2 and 3 and the last school gets all remaining balls.

 The problem reduces to take 11 consecutive spots which we will use to localize the balls and the sticks and select 3 places to put the sticks. The amount of ways to do this is {11 \choose 3} = 165 . As a result, we have 165 ways to distribute the blackboards.

If each school needs at least 1 blackboard you can give 1 blackbooard to each of them first and distribute the remaining 4 the same way we did before. This time there will be 4 balls and 3 sticks, so we have to put 3 sticks in 7 spaces (if a school takes what it is between 2 sticks that doesnt have balls between, then that school only gets the first blackboard we assigned to it previously). The amount of ways to localize the sticks is {7 \choose 3} = 35. Thus, there are only 35 ways to distribute the blackboards in this case.

4 0
4 years ago
If a fourth plant produces 400 widgets in 60 days, which statement is true?
USPshnik [31]
The complete question in the attached figure

the statements are
1) It makes less than plant B
2) It makes the same as plant A
3) It makes more than plant C

we know that
<span>analyzing the graph

</span>plant A
for x=40  y=100
for x=50   y=200
that means 
the production in 10 days is 100 widgets
then
the production in 60 days will be 6*100----> 600 widgets
so
plant A production  > plant fourth production
plant fourth production < plant A production

plant B
for x=40  y=0
for x=60   y=100
that means 
the production in 20 days is 100 widgets
then
the production in 60 days will be 3*100----> 300 widgets
so
plant B production  < plant fourth production
plant fourth production > plant B production

plant C
for x=20  y=0
for x=40   y=100
that means 
the production in 20 days is 100 widgets
then
the production in 60 days will be 3*100----> 300 widgets
plant C production  < plant fourth production
or 
plant fourth production > plant C production

therefore 

the answer is 
3) It makes more than plant C

7 0
3 years ago
Read 2 more answers
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