Solution :
Demand for cola : 100 – 34x + 5y
Demand for cola : 50 + 3x – 16y
Therefore, total revenue :
x(100 – 34x + 5y) + y(50 + 3x – 16y)
R(x,y) = 

In order to maximize the revenue, set



.............(i)


.............(ii)
Solving (i) and (ii),
4 x (i) ⇒ 272x - 32y = 400
(ii) ⇒ (-<u>) 8x - 32y = -50 </u>
264x = 450
∴ 

So, x ≈ $ 1.70 and y = $ 1.99
R(1.70, 1.99) = $ 134.94
Thus, 1.70 dollars per cola
1.99 dollars per iced ted to maximize the revenue.
Maximum revenue = $ 134.94
1) 10%
2)12%
3)20%
4)8%
5)50%
Let's calculate r of this G.P: (-20)/(4) = - 5(100)/(-20) = - 5So r = -5
The formula to find the nth term of a GP is;
a(n) = a(r)ⁿ⁻¹
<u />a₆ = a(r)⁶⁻¹
a₆ = 4(-5)⁵ = -12500<u />
Answer:
y=-5/3x-2
Step-by-step explanation:
<u>Answer:</u>
Below!
<u>Step-by-step explanation:</u>
<u>The best way to answer this question is to read the statement carefully.</u>
- => Five less than twice a number = 2x - 5
- => Five times the sum of two numbers = 5(x + y)
- => The difference of 5 and a number, squared = (5 - x)²
Hoped this helped.
