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Karo-lina-s [1.5K]
2 years ago
14

A jet travels 590 miles in 5 hours; how far can it travel in 11 hours. With an explanation.

Mathematics
2 answers:
White raven [17]2 years ago
5 0
First divide 590 by 5 which equals 118
then take 118 and multiply by 11 which equals 1298 miles. the jet will be able to travel 1298 miles in 11 hours
Akimi4 [234]2 years ago
4 0

Answer:

1298 mi

Step-by-step explanation:

In 5 hours, a jet would travel 5 times the distance that it would if it were to travel for one hour. This means that 590 is five times the distance of one hour. So, 590 divided by 5 is 118, so the jet travels 118 miles in one hour(this is basically the speed).

We can do the reverse to find how far it can travel in 11 hours given the jet travels 118 miles an hour. Using the same logic, the jet would travel 118 in each of the 11 hours, which is 118 x 11: 1298 mi.

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<u>Part 2</u>

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We need to make sure the radical is defined, meaning the radicand has to be non-negative. Thus,

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Each of these extreme value problems has a solution with both a maximum value and a minimum value. Use Lagrange multipliers to f
tino4ka555 [31]

Answer:

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Step-by-step explanation:

Explanation:-

Extreme value :-  f(a, b) is said to be an extreme value of given function 'f' , if it is a maximum or minimum value.

i) the necessary and sufficient condition for f(x)  to have a maximum or minimum at given point.

ii)  find first derivative f^{l} (x) and equating zero

iii) solve and find 'x' values

iv) Find second derivative f^{ll}(x) >0 then find the minimum value at x=a

v) Find second derivative f^{ll}(x) then find the maximum value at x=a

Problem:-

Given function is f(x) = log ( x^2 +1)

<u>step1:</u>- find first derivative f^{l} (x) and equating zero

  f^{l}(x) = \frac{1}{x^2+1} \frac{d}{dx}(x^2+1)

f^{l}(x) = \frac{1}{x^2+1} (2x)  ……………(1)

f^{l}(x) = \frac{1}{x^2+1} (2x)=0

the point is x=0

<u>step2:-</u>

Again differentiating with respective to 'x', we get

f^{ll}(x)=\frac{x^2+1(2)-2x(2x)}{(x^2+1)^2}

on simplification , we get

f^{ll}(x) = \frac{-2x^2+2}{(x^2+1)^2}

put x= 0 we get f^{ll}(0) = \frac{2}{(1)^2}   > 0

f^{ll}(x) >0 then find the minimum value at x=0

<u>Final answer</u>:-

The minimum value of the given function is f(0) = 0

5 0
3 years ago
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