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2 years ago

Write an equation of the line that passes through the points. (0,1),(−2,−5)

Mathematics

2 answers:

Arada [10]2 years ago

6 0

Answer:

y=4/-2

Step-by-step explanation:

I think that is the answer

stepan [7]2 years ago

4 0

Answer:

$y=3x+1$

Step-by-step explanation:

Given the following question:

Point A = (0, 1) = (x1, y1)
Point B = (-2, -5) = (x2, y2)

In order to find the answer, we must first find the slope of the two given points by using rise over run.

$m=\frac{y2-y1}{x2-x1}$
$m=\frac{-5-1}{-2-0}$
$m=\frac{-5-1}{-2-0} =\frac{-6}{-2}$
$=\frac{-6}{-2} =-6\div-2=3$
$m=3$

Now that we know the slope, we can now write the equation in slope intercept form.

$y=mx+b$
$m=3$
$y=1$
$x=0$
<u>
Substitute:</u>

$1=3(0)+b$
$3\times0=0$
$1=b$
$b=1$
$y=3x+1$

Hope this helps.

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Choose the ratios for sin A and cos A.

Irina18 [472]

Answer: D

Step-by-step explanation: By using SOH for sin A, 'S' being sin, 'O' being opposite side of angle A and 'H' being the hypotenuse which is the longest part of the triangle you would find that 15 is opposite from Sin A and 17 the hypotenuse, 15/17.

For cos A you would use CAH, C= cos, A which is the adjacent of the triangle located next to angel A which is 8, and H= hypotenuse (also note that the hypotenuse never changes even if the angle may be different) CAH would be cos A = 8/17

7 0

2 years ago

suppose there are 12 year,14 year,and 16 year cicadas that all appear this yest.after how many years will all three types of cic

nasty-shy [4]

We have to find LCM of 12,14,16

Refer to the attachment

LCM=2×2×2×2×3×7=16×21=336years

5 0

2 years ago

8. A triangle has sides with lengths of 6, 8, and 10 units, and a square has a

svet-max [94.6K]

Difference between the area of the triangle and square is 25

Step-by-step explanation:

Step 1: Find the area of the triangle given its 3 sides using the Heron's formula.

Area of the triangle = $\sqrt{s (s-a)(s-b)(s-c)}$ where s = $\frac{a + b + c}{2}$

⇒ s = (6 + 8 + 10)/2 = 24/2 = 12

$\sqrt{s(s-a)(s-b)(s-c)}$ = $\sqrt{12(12-6)(12-8)(12-10)}$

= $\sqrt{12(6)(4)(2)}$ = $\sqrt{576}$ = 24 sq. units

Step 2: Find the area of the square with perimeter = 28 units.

Perimeter of the square = 4 × side = 28

⇒ Side of the square = 28/4 = 7 units

⇒ Area of the square = (side)² = 7² = 49 sq. units

Step 3: Find the difference between the area of the square and triangle.

Difference = 49 - 24 = 25

8 0

2 years ago

A manufacturer uses production method to produce steel rods. A random sample of 17 steel rods resulted in lengths with a standar

Arisa [49]

Answer:

$\chi^2 =\frac{17-1}{12.15} 22.09 =15.87$

Traditional method

We can find a critical value in the chi square distribution with df =16 who accumulates $\alpha/2 =0.05$ of the area on each tail and we got:

$\chi^2_{crit}= 7.962$

$\chi^2_{crit}=26.296$

Since the calculated value is between the two critical values we don't have enough evidence to conclude that the true deviation is NOT significantly different from 3.5 cm

Confidence level method

We can find the p value like this

$p_v =2*P(\chi^2 >15.87)=0.92$

Since the p value is higher then the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is NOT significantly different from 3.5 cm

Step-by-step explanation:

Data provided

$n=17$ represent the sample selected

$\alpha=0.1$ represent the significance

$s^2 =4.7^2 =22.09$ represent the sample variance

$\sigma^2_0 =3.5^2 =12.15$ represent the value to check

Null and alternative hypothesis

We want to verify if the new production method has lengths with a standard deviation different from 3.5 cm, so the system of hypothesis would be:

Null Hypothesis: $\sigma^2 = 12.15$

Alternative hypothesis: $\sigma^2 \neq 12.15$

The statistic for this case is given by:

$\chi^2 =\frac{n-1}{\sigma^2_0} s^2$

The degrees of freedom are:

$df =n-1= 17-1=16$

$\chi^2 =\frac{17-1}{12.15} 22.09 =15.87$

Traditional method

We can find a critical value in the chi square distribution with df =16 who accumulates $\alpha/2 =0.05$ of the area on each tail and we got:

$\chi^2_{crit}= 7.962$

$\chi^2_{crit}=26.296$

Since the calculated value is between the two critical values we don't have enough evidence to conclude that the true deviation is significantly different from 3.5 cm

Confidence level method

We can find the p value like this

$p_v =2*P(\chi^2 >15.87)=0.92$

Since the p value is higher then the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is significantly different from 3.5 cm

7 0

3 years ago

Help me out here pleaseeeee

Jet001 [13]

Answer:

B {12}

Step-by-step explanation:

;)

3 0

2 years ago