X+(x+2)+(x+4)=3639
3x+6=3639
3x=3633
X=1211
Numbers are: 1211, 1213, 1215
X+(x+2)+(x+4)=672
3x+6=672
3x=666
X=222
Numbers are: 222,224,226
The answer is 2x(2x²+x+1).
When we subtract polynomials we combine like terms:
(9x³+2x²-5x+4)-(5x³-7x+4)
9x³-5x³=4x³
2x²- 0 = 2x²
-5x--7x=-5x+7x=2x
4-4=0
This gives us
4x³+2x²+2x
Each of these is divisible by 2, and each has an x, so we factor those out:
2x( )
4x³/2x = 2x²:
2x(2x² )
2x²/2x=x:
2x(2x²+x )
2x/2x = 1:
2x(2x²+x+1)
Answer:
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Step-by-step explanation:
<span>{[(16 ÷ 4) × (2 × 6)] ÷ 6} + 4 =
</span><span>{[(4) × (12)] ÷ 6} + 4 =
</span>{[4 × 12] ÷ 6} + 4 =
{[48] ÷ 6} + 4 =
{48 ÷ 6} + 4 =
{8} + 4 =
8 + 4 =
12
Answer: Check
12^10 × 12^(-2) = 12^(10 - 2) = 12^8
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Second option : ---
3^2 × 4^6 = 3^2 × 4^2 × 4^4 = 12^2 × 4^4
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Third option : ---
(12^8)^0 = 12^(8 × 0) = 12^0 = 1
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4th option : Check
12^10 / 12^2 = 12^10 × 12^(-2) = 12^(10 - 2)
= 12^8
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5th option : Check
2^8 × 6^8 = ( 2 × 6 )^8 = 12^8
Step-by-step explanation:
