Answer:
1/63
Step-by-step explanation:
Here is the complete question
In an experiment, the probability that event A occurs is 1
/7 and the probability that event B occurs is 1
/9
.
If A and B are independent events, what is the probability that A and B both occur?
Simplify any fractions.
Solution
the probability of independent events A and B occurring is P(A u B) = P(A)×P(B) where P(A) = probability that event A occurs = 1
/7 and P(B) = probability that event B occurs = 1
/9
.
So, P(A u B) = P(A)×P(B) = 1/7 × 1/9 = 1/63
22 quarters= $5.50
10 dimes= $1.00
$5.50 + $1.00 = $6.50
I just did trial and error. I started with 20 quarters and made changes until it worked.
Answer:
12
Step-by-step explanation:
469.75-10.75 =
459 ÷ 38.25 =
12
Answer:
a fraction?
Step-by-step explanation:
question doesn't make sense bruh
