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1 year ago

A stick of gum is 2 inches long. Are 10 sticks of gum longer than 3 feet?

Mathematics

2 answers:

Leona [35]1 year ago

8 0

No it would be 20in so 1 ft and 8in

pashok25 [27]1 year ago

6 0

No not really it would be 20 - 1ft to 8 in

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Sphere A has a radius of 24 centimeters, and sphere B has a diameter of 42 centimeters. The radius of sphere A is

KonstantinChe [14]

Answer:

Step-by-step explanation:

If the diameter of sphere B is 42, that means the radius is half, so it is 21.

The question is asking what multiplied by 24 is 21, or 21 divided by 24. 21/24 can be simplified to 7/8.

5 0

3 years ago

A particle moving in a planar force field has a position vector x that satisfies x'=Ax. The 2×2 matrix A has eigenvalues 4 and 2

andrey2020 [161]

Answer:

The required position of the particle at time t is: $x(t)=\begin{bmatrix}-7.5e^{4t}+1.5e^{2t}\\2.5e^{4t}-1.5e^{2t}\end{bmatrix}$

Step-by-step explanation:

Consider the provided matrix.

$v_1=\begin{bmatrix}-3\\1 \end{bmatrix}$

$v_2=\begin{bmatrix}-1\\1 \end{bmatrix}$

$\lambda_1=4, \lambda_2=2$

The general solution of the equation $x'=Ax$

$x(t)=c_1v_1e^{\lambda_1t}+c_2v_2e^{\lambda_2t}$

Substitute the respective values we get:

$x(t)=c_1\begin{bmatrix}-3\\1 \end{bmatrix}e^{4t}+c_2\begin{bmatrix}-1\\1 \end{bmatrix}e^{2t}$

$x(t)=\begin{bmatrix}-3c_1e^{4t}-c_2e^{2t}\\c_1e^{4t}+c_2e^{2t} \end{bmatrix}$

Substitute initial condition $x(0)=\begin{bmatrix}-6\\1 \end{bmatrix}$

$\begin{bmatrix}-3c_1-c_2\\c_1+c_2 \end{bmatrix}=\begin{bmatrix}-6\\1 \end{bmatrix}$

Reduce matrix to reduced row echelon form.

$\begin{bmatrix} 1& 0 & \frac{5}{2}\\ 0& 1 & \frac{-3}{2}\end{bmatrix}$

Therefore, $c_1=2.5,c_2=1.5$

Thus, the general solution of the equation $x'=Ax$

$x(t)=2.5\begin{bmatrix}-3\\1\end{bmatrix}e^{4t}-1.5\begin{bmatrix}-1\\1 \end{bmatrix}e^{2t}$

$x(t)=\begin{bmatrix}-7.5e^{4t}+1.5e^{2t}\\2.5e^{4t}-1.5e^{2t}\end{bmatrix}$

The required position of the particle at time t is: $x(t)=\begin{bmatrix}-7.5e^{4t}+1.5e^{2t}\\2.5e^{4t}-1.5e^{2t}\end{bmatrix}$

6 0

3 years ago

What is the distance between the points (5.-18) and (8,

romanna [79]

Answer:

$\sqrt{10}$

Step-by-step explanation:

The horizontal distance from points (5,-18) and (8,-17) is 3 because it is 3 units from 5 to 8. The vertical distance is 1 since it is one unit from -18 to -17. Now we can use the equation $a^{2}+b^{2}=c^{2}$ where a=3 and b=1 and c is the distance that you are looking for:

$a^{2} +b^{2} =c^{2}\\3^{2} +1^{2} =c^{2}\\9+1=c^{2}\\10=c^{2}\\\sqrt{10}=c$

8 0

2 years ago

Read 2 more answers

Maggie purchased 8 pounds of ground beef for $18.00. Which of the following does NOT represent the same price per pound?

agasfer [191]

Answer: 5 pounds of ground beef ( don't see second :-( )

Step-by-step explanation: I found the unit rate per pound ( 2.25 ) and then multiplied that by the other pounds to compare the two prices and I only found 5 pounds to be incorrect, but I'll keep digging, hope this helps!

7 0

3 years ago

Q Searchmatics Gr 7)I need 4 cups of flours and 2 cups of sugar to make a cake. How many cups of sugar do I need if Ihave 12 cup

Ede4ka [16]

You will need 6 cups of sugar.

Step - by - Step Explanation

What to find? <em>The number of cups of sugar needed to make a cake with 12 cups of flour.</em>

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Given:

Cups of flours = 4

Cups of sugar = 2

Cups of flour =12

Let x be the number of cups of sugar needed to make a cake with 12 cups of flour.

Using proportion;

4 cups of flour = 2 cups of sugar

12 cups of flour = x

Cross - multiply

4x = 24

Divide both-side of the equation by 4

$\frac{\cancel{4}x}{\cancel{4}}=\frac{24}{4}$

x =6

Hence, you will need 6 cups of sugar.

6 0

1 year ago

A stick of gum is 2 inches long. Are 10 sticks of gum longer than 3 feet? ​

A stick of gum is 2 inches long. Are 10 sticks of gum longer than 3 feet?