Answer:
Their would be 6
1-b, 3-a's, 2-n's
Hope this helps have a great day
Answer:
65625/4(x^5)(y²)
Step-by-step explanation:
Using binomial expansion
Formula: (n k) (a^k)(b ^(n-k))
Where (n k) represents n combination of k (nCk)
From the question k = 5 (i.e. 5th term)
n = 7 (power of expression)
a = 5x
b = -y/2
....................
Solving nCk
n = 7
k = 5
nCk = 7C5
= 7!/(5!2!) ------ Expand Expression
=7 * 6 * 5! /(5! * 2*1)
= 7*6/2
= 21 ------
.........................
Solving (a^k) (b^(n-k))
a = 5x
b = -y/2
k = 5
n = 7
Substituting these values in the expression
(5x)^5 * (-y/2)^(7-5)
= (3125x^5) * (-y/2)²
= 3125x^5 * y²/4
= (3125x^5)(y²)/4
------------------------------------
Multiplying the two expression above
21 * (3125x^5)(y²)/4
= 65625/4(x^5)(y²)
Answer:
<em>(8.21, -20.79)</em>
Step-by-step explanation:
Given the simultaneous equation;
From 2;
a = 29 + b ....3
Substitute 3 into 1;
Factorize
b = -18±√18²-4(-58)/2
b = -18±√324+232/2
b = -18±√556/2
b = -18±23.58/2
b = -18-23.58/2 and -18+23.58/2
b = -41.58/2 and 5.58/2
b = -20.79 and 2.79
Since a = 29 + b
when b = -20.79
a = 29 - 20.79
a = 8.21
<em>Hence the solution to the system of equation is (8.21, -20.79)</em>
Answer:
For each of the possible outcomes add the numbers on the two dice and count how many times this sum is 7. If you do so you will find that the sum is 7 for 6 of the possible outcomes. Thus the sum is a 7 in 6 of the 36 outcomes and hence the probability of rolling a 7 is 6/36 = 1/6.
Step-by-step explanation:
