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navik [9.2K]
2 years ago
6

If x = -1, what is the value of y in the equation?y = 8x3 + 12x2 - 6x - 3

Mathematics
2 answers:
Bezzdna [24]2 years ago
4 0
<h3>Answer:   y = 7</h3>

Work Shown:

y = 8x^3 + 12x^2 - 6x - 3\\\\y = 8(-1)^3 + 12(-1)^2 - 6(-1) - 3\\\\y = 8(-1) + 12(1) - 6(-1) - 3\\\\y = -8 + 12 + 6 - 3\\\\y = 7\\\\

Explanation:

I replaced every x with -1. Then used the order of operations (PEMDAS) to simplify. Keep in mind that (-1)^2 = (-1)*(-1) = 1 and not (-1)^2 = -1

valina [46]2 years ago
4 0

Answer:

The value of y is 7

Step-by-step explanation:

<em>Since </em><em>x=</em><em> </em><em>-</em><em>1</em><em> </em><em>,</em><em> </em><em>To </em><em>find </em><em>the </em><em>value</em><em> </em><em>y </em><em>in</em><em> </em><em>the </em><em>equation</em><em> </em><em>replace</em><em> </em><em>x </em><em>with </em><em>-</em><em>1</em><em> </em><em>.</em><em> </em><em>Solve </em><em>this </em><em>equation</em><em> </em><em>using</em><em> the</em><em> </em><em>order</em><em> </em><em>of </em><em>operation</em><em> </em><em>PEMDAS.</em><em> </em><em>Before</em><em> </em><em>solving</em><em> the</em><em> </em><em>problem,</em><em> </em><em>r</em><em>emember</em><em> this</em><em> in</em><em> </em><em>mind </em><em>-</em><em>1</em><em>³</em><em>=</em><em> </em><em>-</em><em>1</em><em> </em><em>×</em><em> </em><em>-</em><em>1</em><em> </em><em>×</em><em> </em><em>-</em><em>1</em><em> </em><em>=</em><em> </em><em>-</em><em>1</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>-</em><em>1</em><em> </em><em>=</em><em> </em><em>-</em><em>1</em><em> </em><em>×</em><em> </em><em>-</em><em>1</em><em> </em><em>=</em><em> </em><em>1</em>

<em> </em><em> </em><em> </em><em> </em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>y</em><em> </em><em>=</em><em> </em><em>8</em><em>x</em><em>³</em><em> </em><em>+</em><em> </em><em>1</em><em>2</em><em>x</em><em>²</em><em> </em><em>-</em><em> </em><em>6</em><em>x</em><em> </em><em>-</em><em> </em><em>3</em>

<em> </em><em> </em><em>P(</em><em>Exponent</em><em>)</em><em>MDAS </em><em>solve</em><em> </em><em>the</em><em> exponent</em>

<h3><em> </em><em> </em><em>y </em><em>=</em><em> </em><em>8</em><em>(</em><em>-</em><em>1</em><em>)</em><em>³</em><em> </em><em>+</em><em> </em><em>1</em><em>2</em><em>(</em><em>-</em><em>1</em><em>)</em><em>²</em><em> </em><em>-</em><em> </em><em>6</em><em>(</em><em>-</em><em>1</em><em>)</em><em> </em><em>-</em><em> </em><em>3</em></h3><h3><em>y = 8(-1) + 12(1) - 6(-1) -3</em></h3>

<em>PE(Multiplication)DAS , Multiply 8 and -1, 12 and 1, -6 and -1 .</em>

<h3><em>y = -8 + 12 + 6 - 3</em></h3>

<em>PEMD(</em><em>Addition</em><em>)</em><em>S </em><em>,</em><em> </em><em>Add </em><em>-</em><em>8</em><em>,</em><em>1</em><em>2</em><em> </em><em>and </em><em>6</em>

<h3><em>y = 10-3</em></h3>

<em>PEMDA</em><em>(</em><em>Subtraction)</em><em> </em><em>,</em><em> </em><em>subtract </em><em>3</em><em> </em><em>from</em><em> </em><em>1</em><em>0</em>

<h3><em>y </em><em>=</em><em> </em><em>7</em></h3>

<em>The </em><em>value</em><em> of</em><em> </em><em>y </em><em>in </em><em>the</em><em> </em><em>equation </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>y = 8x³ + 12x² - 6x - 3</em><em> </em><em>is</em><em> </em><em> </em><em>7</em>

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