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2 years ago

If x = -1, what is the value of y in the equation?y = 8x3 + 12x2 - 6x - 3

Mathematics

2 answers:

Bezzdna [24]2 years ago

4 0

<h3>Answer: y = 7</h3>

Work Shown:

$y = 8x^3 + 12x^2 - 6x - 3\\\\y = 8(-1)^3 + 12(-1)^2 - 6(-1) - 3\\\\y = 8(-1) + 12(1) - 6(-1) - 3\\\\y = -8 + 12 + 6 - 3\\\\y = 7\\\\$

Explanation:

I replaced every x with -1. Then used the order of operations (PEMDAS) to simplify. Keep in mind that $(-1)^2 = (-1)*(-1) = 1$ and not $(-1)^2 = -1$

valina [46]2 years ago

4 0

Answer:

The value of y is 7

Step-by-step explanation:

Since x= -1 , To find the value y in the equation replace x with -1 . Solve this equation using the order of operation PEMDAS. Before solving the problem, remember this in mind -1³= -1 × -1 × -1 = -1

-1 = -1 × -1 = 1

y = 8x³ + 12x² - 6x - 3

P(Exponent)MDAS solve the exponent

PE(Multiplication)DAS , Multiply 8 and -1, 12 and 1, -6 and -1 .

PEMD(Addition)S , Add -8,12 and 6

PEMDA(Subtraction) , subtract 3 from 10

The value of y in the equation y = 8x³ + 12x² - 6x - 3 is 7

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Answer:

5) 729, an=3^n, a[1]=3; a[n]=3·a[n-1]

6) 1792, an=7(4^(n-1)), a[1]=7; a[n]=4·a[n-1]

Step-by-step explanation:

The next term of a geometric sequence is the last term multiplied by the common ratio. (This is the basis of the recursive formula.)

The Explicit Rule is ...

$a_n=a_1\cdot r^{n-1}$

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The Recursive Rule is ...

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Recursive rule: a[1] = 3; a[n] = 3·a[n-1]

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Recursive rule: a[1] = 7; a[n] = 4·a[n-1]

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