Answer:
The phenotypic ratio will be 3:1
Explanation:
As per this question there are two phenotypes for seed color, yellow and green. Both the parents are true breeding that means they are homozygous for this trait. Also, all the F1 plants have yellow seed color which clearly indicates that yellow seed color is a dominant trait while green is recessive trait.
The cross of true breeding plants as mentioned above is depicted as under:
Parents YY x yy
/ \ / \
F1 generation Yy Yy Yy Yy
So, as per the law of dominance because of the presence of Y allele, all these progeny will be yellow in color.
Next, when these F1 plants will be crossed, the result will be as under:
F1 generation Yy x Yy
/ \ / \
F2 generation YY Yy Yy yy
The genotypic ratio of F2 generation is 1:2:1
The phenotypic ratio of F2 generation is 3:1
It simply means that in F2 generation, 3 progeny which have allelic combination YY & Yy will be yellow colored while 1 progeny which has allelic combination yy will have green color.
If I am understanding the choices correctly, the answer would be Convection Currents.
Hope this helps!
The necessary actions are
<span>- Inform the patient about her rights
</span><span>- Obtain consent from the patient
</span>
To be ethical, we should fully give informations to the perinatal patient about research without concealing anything. Including the potential side effects of the research and the payment/benefit that they patients would get if they agree to be a part of it
Answer:
The correct order is F, E, C, G, H, A, D, and B (look at the image in the attached files)
Explanation:
- <u>Interphase</u><u>:</u> Stages G1, S, and G2. At this point probably, the chromatin duplication has already occurred, but it is still lax or dispersed. It has not condensed yet. Two pairs of centrioles are outside the nucleus (FIGURE F)
- <u>Prophase</u>: Centrioles move forward to the opposite poles of the cell. Chromatin is condensed and individual chromosomes are now visible. The nuclear membrane breaks into many pieces. Spindle apparatus -microtubules- forms. (FIGURE E)
- <u>Metaphase:</u> The polar and the kinetochore fibers drive each individual chromosome to the equatorial plane. This stage ends when all the chromosomes are completely arranged in the medial area. (FIGURE C)
- <u>Anaphase</u>: Sister chromatids separate and move to the opposite poles of the cells, driven by the microtubules. In each pole, there are a pair of centrioles (FIGURE G and H).
- <u>Telophase</u>: The nuclear membrane rearranges. Each sister chromatid becomes now a new chromosome. There is a pair of centrioles outside each of the nuclei. (FIGURE A)
- Cytokinesis occurs at the end of the cell division. The rest of the cell is divided into two new daughter cells. Each daughter cell is an identical copy of the other cell, with the exact same genetic material (FIGURE D).
- Decondensation of the genetic material of each new cell (FIGURE B).
Answer:
According to the image, the approximate QT interval is 0.4 seconds.
Explanation:
The QT interval is the space between the beginning of the QRS complex and the end of the T wave, which represents from the beginning of depolarization to ventricular repolarization.
Considering that the extandardized measurements of an EKG, where the paper circulates at a speed of 25 mm/s, 1 mm horizontal —measuring time— has an equivalence of 0.04 s.
In the image, there is 10 mm between the beginning of the QRS and the end of the T wave, so:
0.04 seconds X 10 mm = 0.4 seconds.
Then, the estimated QT interval is 0.4 seconds.
