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nignag [31]
3 years ago
9

Solve for z 2 + -z = 5

Mathematics
2 answers:
Mariana [72]3 years ago
6 0

I’m pretty sure the answer is 3 because the z stands for a missing number so 2+3=5

NARA [144]3 years ago
6 0

Simplify both sides of the equation.

2+-z=5

-z+2=5

Subtract 2 from both sides.

-z+2-2=5-2

-z=3

Divide both sides by -1

-z = 3

-1 = -1

z=-3

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Read 2 more answers
Solve x2 – 10x + 25 = 35 for x.
Galina-37 [17]

x^2-10x+25=35\\\\x^2-2\cdot5\cdot x + 5^2=35\ \ \ |\text{use:}\ (a-b)^2=a^2-2ab+b^2\\\\(x-5)^2=35\to x-5=\pm\sqrt{35}\ \ \ |+5\\\\\boxed{x=5-\sqrt{35}\ \vee\ x=5+\sqrt{35}}


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3 0
3 years ago
G(x)=−2(x+1)(x+7) find the zeros
Makovka662 [10]
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3 0
3 years ago
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Oksanka [162]

9514 1404 393

Answer:

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Step-by-step explanation:

The other root is the conjugate of the given one, so is 2-√2. The quadratic equation in factored form is then ...

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Expanding this, we get ...

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  x^2 -4x +2 = 0 . . . . the equation you're looking for

4 0
3 years ago
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