If the length, breadth and height of the box is denoted by a, b and h respectively, then V=a×b×h =32, and so h=32/ab. Now we have to maximize the surface area (lateral and the bottom) A = (2ah+2bh)+ab =2h(a+b)+ab = [64(a+b)/ab]+ab =64[(1/b)+(1/a)]+ab.
We treat A as a function of the variables and b and equating its partial derivatives with respect to a and b to 0. This gives {-64/(a^2)}+b=0, which means b=64/a^2. Since A(a,b) is symmetric in a and b, partial differentiation with respect to b gives a=64/b^2, ==>a=64[(a^2)/64}^2 =(a^4)/64. From this we get a=0 or a^3=64, which has the only real solution a=4. From the above relations or by symmetry, we get b=0 or b=4. For a=0 or b=0, the value of V is 0 and so are inadmissible. For a=4=b, we get h=32/ab =32/16 = 2.
Therefore the box has length and breadth as 4 ft each and a height of 2 ft.
Answer:
74 is tha answer
Step-by-step explanation:
Answer: Im pretty sure it is the equal sign with the line between it
pretty sure that is it tho
Hope that helped
Step-by-step explanation:
<h3>
Answer:</h3>
<h3>
Explanation:</h3>
Represent the sentence mathematically. 
Distribute. 
Add 6 on both sides. 
Divide both sides by 2.
we know that
If line b is perpendicular to line a, and line c is perpendicular to line a,
then
line b and line c are parallel
and two lines parallel have the same slope
so
<u>Find the slope of the line b</u>
Let
The formula to calculate the slope between two points is equal to
substitute
therefore
<u>the answer is</u>
<u>the slope of the line c is</u>
