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3 years ago

When two numbers are not equal, an a0 is a sentence that uses the symbols >, <, ≥, ≤, or ≠ to show a relationship.

Mathematics

2 answers:

Naddik [55]3 years ago

8 0

Answer: Im pretty sure it is the equal sign with the line between it

pretty sure that is it tho

Hope that helped

Step-by-step explanation:

irga5000 [103]3 years ago

4 0

Answer:

$\huge \boxed{\mathrm{inequality }}$

$\rule[225]{225}{2}$

Step-by-step explanation:

An inequality is a sentence that uses the symbols >, <, ≥, ≤, or ≠ to show a relationship.

An inequality shows that two numbers are not necessarily equal.

$\rule[225]{225}{2}$

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A woman bought some large frames for $19 each and some small frames for $9 each at a closeout sale. If she bought 18 frames for

MAXImum [283]

Answer: 6 large frames and 12 small frames

Step-by-step explanation:

We define the following:

x = number of large frames

y = number of small frames

Make the following equations:

x + y = 18

19x + 9y = 222

Use system of equations to solve. We find the value of x first.

y = 18 - x

⇒ 19x + 9(18 - x) = 222

⇒ 19x + 162 - 9x = 222

⇒ 10x + 162 = 222

⇒ 10x = 60

⇒ x = 6

Find value of y:

6 + y = 18

y = 12

∴ 6 large frames and 12 small frames were purchased.

8 0

2 years ago

Again can you guys help me

Hatshy [7]

Answer:

Step-by-step explanation:

slope= rise/run

y-intercept= where the slope intersects with the y-axis

have a great day! :)

5 0

3 years ago

Somebody help me please because i’m stuck

worty [1.4K]

The question is asking for you to plug in each number in the brackets into x and solve for y, or f(x), g(x), etc. I will do no. 19 as an example:

f(x) = -3x + 1

This problem has the domains -2, -1, and 0. First, we'll start with -2:

f(x) = -3(-2) + 1

f(x) = 6 + 1

f(x) = 7

Now -1:

f(x) = -3(-1) + 1

f(x) = 3 + 1

f(x) = 4

Lastly, 0:

f(x) = -3(0) + 1

f(x) = 0 + 1

f(x) = 1

For question 23, we can use the distance formula, which is ratextime. The domain in this case is time (t). You can set up a function like this: d(t) = 60t

8 0

3 years ago

Help did i get this answer right

4vir4ik [10]

I do believe it would be a 2.2

3 0

3 years ago

Prove that sin20sin40sin60sin80=3/16

never [62]

We'll use the following properties of sine and cosine to prove this:

$sin(a)\cdot sin(b) = \frac12(cos(a-b) - cos(a+b))$

$cos(a)\cdot cos(b) = \frac12(cos(a+b) + cos(a-b))$

$cos(180+a) = cos(180-a)$

Then it's just a matter of filling it in...

sin20sin40 * sin60sin80 = 1/2(cos20 - cos60) * 1/2 (cos20 - cos140) =

1/8( cos40 + 1 - cos160 - cos120 - cos40 - cos80 + cos80 + cos200) =

1/8(1 - cos160 - cos120 + cos200) =

1/8(1 - cos160 - cos120 + cos160) =

1/8(1 - cos120 ) = 1/8( 1 + 1/2 ) = 3/16

5 0

4 years ago