Notice that the 2 expressions have 2 common terms.
(r-s) is just (s-r) times (-1)
similarly
(t-s) is just (s-t) times (-1)
this means that :
(r-s) (t-s) + (s-r) (s-t)=-(s-r)[-(s-t)]+(s-r) (s-t)
the 2 minuses in the first multiplication cancel each other so we have:
-(s-r)[-(s-t)]+(s-r) (s-t)=(s-r) (s-t)+(s-r) (s-t)=2(s-r) (s-t)
Answer:
d)<span>2(s-r) (t-s) </span>
Answer:
x=3
Step-by-step explanation:
First would need to convert the radical into a number.
And since if you have a perfect square of a radical it goes outside the square root sign, you would take the 3 and square it to make 9 and then take the 2 inside the square root sign and multiply so you have the square root of 18|
Since we have
as the Leg c we would need to square it, squaring a square root sign would just cause them to be cancelled out and you being left with 18, afterwards find the square of 3, which is 9
18-9=9
square root of 9 = 3
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Answer:
196
Step-by-step explanation:
Given that the significance level of 2% = α
Because the the null hypothesis is true so it is denoted by α it also defined as the level of significance =1 - confidence level = 1 - 0.02 = 0.98.
So the number of the tests will incorrectly find significance:
=0.98×200=196